Phenylamine and Azo Compounds
Quick Notes
- Phenylamine can be prepared from benzene in two steps:
- Benzene to nitrobenzene (via HNO3/H2SO4)
- Then reduction using Sn/HCl + NaOH
- Phenylamine reactions:
- Reacts with Br2(aq) to form a tribromo derivative.
- Reacts with NaNO2 + HCl (<10 °C) to form benzenediazonium salt.
- Warming the diazonium salt forms phenol.
- Basicity: Ethylamine > ammonia > phenylamine, due to availability of the nitrogen lone pair.
- Azo compounds:
- Formed by coupling a diazonium salt with a phenol or aromatic amine.
- The azo group is –N=N–.
- Azo compounds are widely used as dyes due to their extended conjugation and vivid colours.
Full Notes
Preparation of Phenylamine
Phenylamine can be formed from benzene in a series of steps.

Step 1: Nitration of Benzene

- Reagents: Concentrated HNO3 and concentrated H2SO4
- Conditions: 50–60 °C
- Reaction: C6H6 + HNO3 → C6H5NO2 + H2O (Forms nitrobenzene)
Step 2: Reduction of Nitrobenzene to Phenylamine

- Reagents: Tin (Sn) and concentrated HCl
- Followed by: Neutralisation with NaOH(aq)
- Reaction: C6H5NO2 + 6[H] → C6H5NH2 + 2H2O
- Phenylamine is formed.
Reactions of Phenylamine
The following are reactions of phenylamine you need to know.
Reaction with Bromine Water

- Reagents: Br2(aq), room temperature
- Observation: Orange Br2 is decolourised, and a white precipitate forms.
- Product: 2,4,6-tribromophenylamine
This is an example of electrophilic substitution. The –NH2 group activates the benzene ring, making it more reactive towards substitution, especially at the 2, 4, and 6 positions.
Forming Diazonium Salt and Formation of Phenol

- Reagents: NaNO2 + dilute HCl at below 10 °C
- Reaction: C6H5NH2 + HNO2 + HCl → C6H5N2+Cl− + 2H2O
- (Forms benzenediazonium chloride)
Warming the diazonium salt with water:
- Reaction: C6H5N2+Cl− + H2O → C6H5OH + N2 + HCl
- (Forms phenol and nitrogen gas)
Relative Basicity of Ammonia, Ethylamine and Phenylamine
Basicity depends on how available the nitrogen's lone pair is for accepting a proton (H+).
Order of basicity: Ethylamine > ammonia > phenylamine

- Ethylamine has an electron-donating alkyl group (CH3CH2–) that increases electron density on the N atom, making the lone pair more available.
- Ammonia has no such group.
- Phenylamine has its lone pair delocalised into the benzene ring, making it less available to accept a proton, so it's a weaker base.
Azo Compounds
Azo compounds are formed in coupling reactions and contain the –N=N– functional group.

The Azo functional group joins two aromatic rings and extends the conjugation (delocalised pi-bonding system), allowing absorption of visible light.
Coupling Reaction

- Diazonium salt reacts with phenol or an aromatic amine under alkaline conditions.
- Example: C6H5N2+ + C6H5OH → C6H5–N=N–C6H4OH (Azo dye)
Use in Dyes
Azo compounds are widely used in textile dyes, indicators, and pigments. Their colour varies depending on the groups attached to the benzene rings. Other azo dyes can be formed by similar reactions using different phenols or amines, yielding a wide range of coloured dyes.
Summary
- Phenylamine is prepared from benzene via nitration then reduction.
- It reacts with Br2(aq) to form tribromophenylamine, and with NaNO2/HCl to form a diazonium salt (which can give phenol when warmed).
- Relative basicity: Ethylamine > ammonia > phenylamine (due to lone pair availability).
- Azo compounds contain –N=N–, formed by coupling diazonium salts with phenols or amines, and are important dyes.