Enthalpies of solution and hydration
Quick Notes
- Enthalpy change of solution (ΔHsol):
- The energy change when 1 mole of an ionic solid dissolves in water (to form an infinitely dilute solution).
- Enthalpy change of hydration (ΔHhyd):
- the energy released when 1 mole of gaseous ions dissolves in water (to form an infinitely dilute solution).
- We can construct energy cycles using enthalpies of solution, lattice energy and enthalpies of hydration for an ionic compound.

- Higher ionic charge and smaller ionic radius gives a more exothermic enthalpy of hydration (ΔHhyd).
Full Notes
Enthalpies of solution and hydration have been outlined in more detail
here.
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Key Definitions
Enthalpy of solution (ΔHsol):
The enthalpy change when 1 mole of an ionic compound dissolves in enough water to form an infinitely dilute solution.

Example NaCl(s) → Na⁺(aq) + Cl⁻(aq)
Enthalpy of hydration (ΔHhyd):
The enthalpy change when 1 mole of gaseous ions dissolves in water to form aqueous ions.

Example
Na⁺(g) → Na⁺(aq)
Cl⁻(g) → Cl⁻(aq)
Energy Cycle for Solution Enthalpy
An energy cycle can be constructed that links enthalpy of solution (ΔHsol), hydration enthalpies (ΔHhyd) and lattice energy (ΔHlatt):


For these energy cycles, the lattice energy is given as a positive value as the arrow direction is going from the ionic solid to the gaseous ions, this is breaking apart the lattice. This is the exact same value as lattice energy however it has a positive sign (+ΔH) rather than negative as it is an endothermic process.
Energy cycle equation:

- ΔHlatt is positive (energy needed to break lattice)
- ΔHhyd is negative (energy released when ions are hydrated)
Worked Example Calculation
Calculate ΔHsol, given:
- ΔHlatt (NaCl) = +769 kJ mol⁻¹
- ΔHhyd (Na⁺) = –406 kJ mol⁻¹
- ΔHhyd (Cl⁻) = –364 kJ mol⁻¹
Calculate ΔHsol: ΔHsol = +769 + (–406) + (–364)
ΔHsol = –1 kJ mol⁻¹
So, dissolving NaCl is slightly exothermic.
Factors Affecting Enthalpy of Hydration
The magnitude of ΔHhyd depends on:
- Ionic charge:
Higher charge = stronger attraction to water = more exothermic ΔHhyd.
Example Mg²⁺ has more negative ΔHhyd than Na⁺. - Ionic radius:
Smaller ions = stronger electrostatic attraction to water = more exothermic ΔHhyd.
Example Li⁺ is more exothermic than Cs⁺.
So, small, highly charged ions have more exothermic hydration enthalpies.
Summary
- ΔHsol: enthalpy change when 1 mole of ionic solid dissolves in water.
- ΔHhyd: enthalpy change when 1 mole of gaseous ions dissolves in water.
- Energy cycles link ΔHsol, ΔHhyd, and ΔHlatt.
- ΔHlatt is positive (breaking lattice), ΔHhyd is negative (hydrating ions).
- Worked example: ΔHsol for NaCl = –1 kJ mol⁻¹.
- Smaller, more highly charged ions have more exothermic hydration enthalpies.