Hess’s Law
Quick Notes
- Hess’s Law: The total enthalpy change in a chemical reaction is independent of the route taken, as long as the starting and ending conditions are the same.
- We can use Hess (energy) cycles to determine enthalpy changes that can’t be found directly by experiment.
- Key formulas:
- ΔHr = ΣΔHf(products) – ΣΔHf(reactants)
- ΔHr = ΣΔHc(reactants) – ΣΔHc(products)
- ΔHr = Bonds broken – Bonds made
Full Notes
Hess’s Law has been outlined with more background theory and detail at
this page.
This page is just what you need to know for CIE A-Level Chemistry :)
What is Hess’s Law?
Hess’s Law states:
“The total enthalpy change for a reaction is the same, no matter which route is taken, provided the starting and finishing conditions are the same.”
This is based on the Law of Conservation of Energy which states that energy cannot be created or destroyed, only transferred.
Hess’s Law is useful for finding enthalpy changes that cannot be measured directly by using Hess cycles (energy cycles).

A Hess’s cycle can be constructed for:
- Enthalpy of formation (ΔHf) calculations
- Enthalpy of combustion (ΔHc) calculations
Hess’s Cycles Using Enthalpies of Formation (ΔHf)
The enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.
Elements in their standard states (for example, O2(g)) have an enthalpy of formation, ΔHf, of zero — this is really important for calculations involving standard enthalpies of formation.
Formula for Hess’s Cycle using enthalpy of formation:
ΔHr = ΣΔHf(products) – ΣΔHf(reactants)
Calculate the enthalpy of formation of CO2
Reaction:
C(s) + O2(g) → CO2(g)
Given Data:
ΔHf(CO2) = –393 kJ mol⁻¹
ΔHf(O2) = 0 (since elements in their standard states have ΔHf = 0)
Using Hess’s Law:
ΔHr = ΔHf(CO2) – (ΔHf(C) + ΔHf(O))
ΔHr = –393 – (0 + 0)
ΔHr = –393 kJ mol⁻¹
Hess’s Cycles Using Enthalpies of Combustion (ΔHc)
Using enthalpies of combustion to find the enthalpy of formation of propane (C3H8)
Given Data:
ΔHc(C(s)) = –394 kJ mol⁻¹
ΔHc(H2(g)) = –286 kJ mol⁻¹
ΔHc(C3H8(g)) = –2220 kJ mol⁻¹
Draw a Hess Cycle showing two possible routes:

Using Hess’s Law we know route 1 = route 2
ΔH1 = ΔH? + ΔH2
ΔH? = ΔH1 – ΔH2
ΔH? = (–2326) – (–2220) = –106 kJ mol⁻¹
Hess’s Law Using Bond Energies
Calculate the enthalpy change of formation (ΔHf) of methane, CH4(g) using bond enthalpies.
Bond enthalpies (kJ mol⁻¹):
C–H = +412
H–H = +436
C(s) → C(g) = +716
ΔHf of H2(g): 0.5H2(g) → H(g) + H(g), ΔH = +218
Overall reaction: C(s) + 2H2(g) → CH4(g)
Step 1: Draw the Hess Cycle

Step 2: Apply Hess’s Law

ΔHf = ΔH1 (atomise C) + ΔH2 (atomise H2) – ΔH3 (form CH4)
ΔHf = +716 + 872 – 1648 = –60 kJ mol⁻¹
Final Answer:
ΔHf(CH4) = –60 kJ mol⁻¹

Always label arrows with enthalpy values and direction.
Make sure all equations in the cycle balance properly.
Pay careful attention to states — for example, if dealing with bond enthalpies make sure substances are atomised to get them into free, gaseous atoms. 0.5H2(g) isn’t the same as H(g).
Keep units consistent (usually kJ mol⁻¹).
Summary
- Hess’s Law states enthalpy change is independent of reaction route.
- Hess cycles allow calculation of ΔH values that cannot be measured directly.
- Standard enthalpy of formation (ΔHf) of elements in standard states = 0.
- ΔHr can be calculated using ΔHf, ΔHc, or bond energies.
- Always balance equations, check states, and keep units consistent.