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17 Carbonyl compounds

17.1 Aldehydes and ketones

Aldehydes and Ketones

Specification Reference Organic Chemistry, Carbonyl compounds 17.1

Quick Notes

  • Aldehydes can be made by the oxidation of a primary alcohol with acidified K2Cr2O7 or KMnO4 (aldehyde collected by distillation).
  • Ketones can be made by the oxidation of a secondary alcohol with acidified K2Cr2O7 or KMnO4
  • Reactions of Aldehydes and Ketones:
    • Reduction to Alcohols:
      Use NaBH4 or LiAlH4.
      Aldehydes form primary alcohols
      Ketones form secondary alcohols
    • Reaction with HCN/KCN:
      Forms hydroxynitriles (adds –OH and –CN across the C=O group).
      Occurs via nucleophilic addition.
  • Tests for Carbonyl Compounds:
    • 2,4-DNPH Test:
      Reacts with both aldehydes and ketones → orange precipitate.
    • Fehling’s Solution / Tollens’ Reagent:
      Distinguish between aldehydes and ketones.
      Aldehydes are easily oxidised → give a positive result.
      (Fehling’s: red ppt, Tollens’: silver mirror).
      Ketones give no reaction.
    • Iodoform Test (I2/OH):
      Detects a CH3CO– group (typically methyl ketones or ethanal).
      Gives a yellow precipitate of CHI3 (iodoform) with antiseptic smell.

Full Notes

Aldehydes and ketones and their reactions have been outlined in more detail here.
This page is just what you need to know for CIE A-level Chemistry :)

Aldehydes and ketones contain a carbonyl (C=O) functional group.

Making Aldehydes

Oxidation of Primary Alcohols

Aldehydes can be formed by the oxidation of Primary Alcohols

CIE A-Level Chemistry diagram showing oxidation of a primary alcohol to an aldehyde with distillation.

Note: Distillation prevents further oxidation to a carboxylic acid.

Example CH3CH2OH + [O] → CH3CHO + H2O

Oxidation of Secondary Alcohols

Ketones can be made by the oxidation of Secondary Alcohols

CIE A-Level Chemistry diagram showing oxidation of a secondary alcohol to a ketone.

Note: Ketones do not oxidise further under normal conditions.

Example CH3CH(OH)CH3 → CH3COCH3 + H2O

Key Reactions

Aldehydes and ketones react with nucleophiles as the C=O bond is polar and nucleophiles are attracted to the Cδ+.

Nucleophiles are electron pair donors.

Reduction to Alcohols

Aldehydes and Ketones can be reduced to alcohols

CIE A-Level Chemistry reaction scheme showing reduction of aldehydes and ketones to alcohols using NaBH4 or LiAlH4.

Explanation: H ion from the reducing agent adds to the carbonyl carbon, shown as [H] in equation.

Note - LiAlH4 is a more powerful reducing agent than NaBH4, because of this, if LiAlH4 is used no water can be present and the reaction must be carried out in dry ether.

Example CH3CHO + 2[H] → CH3CH2OH

Photo of Matt
Matt’s exam tip

Remember reduction in organic chemistry is the gaining of a carbon-hydrogen bond. To provide the hydrogen needed, we use reducing agents (such as NaBH4 and LiAlH4) and show hydrogen from a reducing agent in equations as [H].

Reaction with HCN/KCN (Forming Hydroxynitriles)

Carbonyls react with KCN in H2SO4 to form hydroxynitriles.

CIE A-Level Chemistry reaction scheme showing aldehyde/ketone reacting with HCN/KCN to form a hydroxynitrile.

Explanation: Adds CN and H+ across the C=O group to give an extra C–C bond.

Note: HCN is generated in situ by reacting KCN with H2SO4 because pure HCN is too toxic and volatile to handle safely. The KCN supplies CN ions, while H2SO4 provides H+ ions. This combination produces the same product — a hydroxynitrile — without needing to use HCN directly.

Example CH3CHO + HCN → CH3CH(OH)CN

Nucleophilic Addition Mechanism (HCN)

Aldehydes and ketones react by nucleophilic addition mechanisms - a nucleophile starts the reaction by attacking the Cδ+ in the C=O bond.

CIE A-Level Chemistry mechanism diagram of CN− nucleophilic addition to a carbonyl forming a hydroxynitrile.

Steps:

  1. CN attacks the electrophilic carbon in the carbonyl group.
  2. Intermediate forms with a negative charge on oxygen.
  3. H+ (from HCN or acid) adds to O, forming the hydroxynitrile.

Test with 2,4-DNPH

Carbonyl containing compounds (aldehydes and ketones) form an orange precipitate when added to a solution of 2,4-DNPH (Brady’s reagent).

CIE A-Level Chemistry photo/chart showing orange/yellow precipitate with 2,4-DNPH for carbonyl compounds. CIE A-Level Chemistry scheme of hydrazone formation when carbonyl reacts with 2,4-DNPH.

Distinguishing Aldehydes from Ketones

Because aldehydes can be further oxidised, they can be distinguished from ketones using oxidation reactions.

The two main tests used are Fehling's Solution and Tollens' Reagent.

Test Aldehyde (CHO) Ketone
Fehling’s Red ppt of Cu2O No change
Tollens’ Silver mirror forms (Ag0) No silver formed

Fehling’s Solution Test:

CIE A-Level Chemistry test showing brick-red Cu2O precipitate with Fehling’s for aldehydes.

Aldehyde: Forms a brick-red precipitate (Cu2O).
Ketone: No change.

Tollens’ Silver Mirror Test:

CIE A-Level Chemistry test showing silver mirror formation with Tollens’ reagent for aldehydes.

Aldehyde: Forms a silver mirror (Ag).
Ketone: No change.

Iodoform Test (CH3CO– group)

The iodoform test detects compounds with the CH3CO– group (methyl ketones) or ethanal.

CIE A-Level Chemistry reaction showing iodoform (CHI3) formation as a yellow precipitate.

Example CH3COCH3 + 3I2 + 4OH → CHI3 + CH3COO + 3I + 3H2O

Summary