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1 Solutions 2 Electrochemistry 3 Chemical Kinetics 4 The d-and f-Block Elements 5 Coordination Compounds 6 Haloalkanes and Haloarenes 7 Alcohols, Phenols and Ethers 8 Aldehydes, Ketones and Carboxylic Acids 9 Amines 10 Biomolecules

1 Solutions

1.1 Types of Solutions 1.2 Expressing Concentration of Solutions 1.3 Solubility 1.4 Vapour Pressure of Liquid Solutions 1.5 Ideal and Non-ideal Solutions 1.6 Colligative Properties and Determination of Molar Mass 1.7 Abnormal Molar Masses 2.1 Electrochemical Cells 2.2 Galvanic Cells 2.3 Nernst Equation 2.4 Conductance of Electrolytic Solutions 2.5 Electrolytic Cells and Electrolysis 2.6 Batteries 2.7 Fuel Cells 2.8 Corrosion

Electrolytic Cells and Electrolysis

NCERT Reference: Chapter 2 – Electrochemistry – Pages 57–59

Quick Notes

  • Electrolytic cells use external electrical energy to drive non-spontaneous redox reactions.
  • In these cells, anode is positive and cathode is negative (opposite of galvanic cells).
  • Cations move to the cathode (get reduced), and anions to the anode (get oxidised).
  • Inert electrodes (like Pt, graphite) do not participate in the reaction.
  • The products of electrolysis depends on:
    • Electrode potential (preferential discharge of ions)
    • Concentration of ions
    • Nature of the electrodes

Full Notes

Introduction to Electrolytic Cells

Electrolytic cells use electricity to bring about chemical change. They are distinct from galvanic cells because the reactions occurring in electrolytic cells are non-spontaneous, requiring a source of DC power to proceed. The goal is to convert electrical energy into chemical energy.

In an electrolytic cell:

Faraday’s Contribution

Michael Faraday was the first to study electrolysis quantitatively. He formulated two important laws known as Faraday’s Laws of Electrolysis.

Faraday’s First Law of Electrolysis:
The amount of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity (charge) passed through the electrolyte. NCERT Class 12 Chemistry diagram illustrating Faraday’s first law of electrolysis proportionality between mass deposited and charge passed.


Faraday’s Second Law of Electrolysis:
When the same quantity of electricity is passed through different electrolytes, the masses of substances deposited are proportional to their chemical equivalents. NCERT Class 12 Chemistry relation showing masses deposited proportional to chemical equivalents for the same charge.

Charge and the Faraday Constant

Charge (Q) is the product of current (I) in amperes and time (t) in seconds:

NCERT Class 12 Chemistry relation Q equals current times time for electrolysis calculations.

Faraday Constant (F):

Products of Electrolysis

The discharge of ions during electrolysis is not arbitrary – it's influenced by electrochemical principles.

Based on the Electrochemical Series

Ions lower in the electrochemical series (having higher reduction potentials) are preferentially discharged.

Example Na+ vs H+

Between Na+ and H+, H+ is reduced at the cathode due to higher E°.

Based on Ion Concentration

Sometimes, even if an ion is lower in the series, higher concentration can cause it to discharge preferentially.

Example Cl vs OH

At high Cl concentration, Cl gets oxidised in preference to OH, even though OH has a lower oxidation potential.

Based on Electrode Nature

Inert electrodes (Pt, graphite): don’t participate in reactions; only facilitate electron transfer.

Reactive electrodes (Cu, Ag): can participate by getting oxidised or depositing metal.

Molten Electrolytes

When an electrolyte is molten (melted to liquid state), we can predict the products formed at each electrode based on the type of electrolyte being used. This is because only the cations and anions of the compound are present:

Example Electrolysis of molten NaCl

NCERT Class 12 Chemistry diagram of electrolysis of molten sodium chloride showing Na formed at cathode and Cl2 at anode.

Aqueous Electrolytes

When an electrolyte is aqueous (aq), the ionic compound is dissolved in water. Now, H+(aq) and OH(aq) ions from water are also present due to the natural ionisation of water:

2H2O + 2e → H2 + 2OH and 2H2O → O2 + 4H+ + 4e.

As a result, water may compete with the ions from the compound at the electrodes for oxidation and reduction. We can use standard electrode potentials (E° values) or reactivity trends to predict which species is discharged.

Example Electrolysis of aqueous NaCl

NCERT Class 12 Chemistry schematic for electrolysis of aqueous sodium chloride showing competition between water and ions.

This system contains Na+ and H2O (possible reduction at the cathode) and Cl and H2O (possible oxidation at the anode).

Another Example: Electrolysis of Aqueous CuSO4

CuSO4(aq) contains:

  • Cu2+ and SO42− from the salt
  • H2O, which contributes H+ and OH ions

Cathode: Possible Reductions

  • Compare the reduction potentials:
  • Cu2+ + 2e → Cu(s) E° = +0.34 V
  • 2H2O + 2e → H2 + 2OH E° = −0.83 V
  • Copper is reduced, because it has a much more positive E° value than hydrogen gas.
  • Cathode reaction: Cu2+(aq) + 2e → Cu(s)

Anode: Possible Oxidations

  • We compare the reverse of these reduction potentials:
  • S2O82− + 2e → 2SO42− E° = +2.01 V
  • O2 + 4H+ + 4e → 2H2O E° = +1.23 V
  • (Note: Halide ions like Cl are not present.)
  • Since oxidation is the reverse of reduction, the species with the lower E° for reduction is easier to oxidise. Water (E° = +1.23 V) is oxidised more readily than S2O82−.
  • Anode reaction: 2H2O → O2(g) + 4H+ + 4e

Concentration matters:

If halide concentration is very low (e.g., dilute NaCl), OH from water may be oxidised instead.

If the metal ion concentration is very low, hydrogen gas may form instead of metal at the cathode.

Summary