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1 Solutions 2 Electrochemistry 3 Chemical Kinetics 4 The d-and f-Block Elements 5 Coordination Compounds 6 Haloalkanes and Haloarenes 7 Alcohols, Phenols and Ethers 8 Aldehydes, Ketones and Carboxylic Acids 9 Amines 10 Biomolecules

9 Amines

9.1 Structure of Amines 9.2 Classification 9.3 Nomenclature 9.4 Preparation of Amines 9.5 Physical Properties 9.6 Chemical Reactions 9.7 Method of Preparation of Diazonium Salts 9.8 Physical Properties of Diazonium Salts 9.9 Chemical Reactions of Diazonium Salts 9.10 Importance of Diazonium Salts in Synthesis of Aromatic Compounds

Structure of Amines

NCERT Reference: Chapter 9 – Amines – Page 241

Quick Notes

  • Amines are derived from ammonia (NH3) by replacing hydrogen atoms with alkyl or aryl groups.
  • The nitrogen atom in amines is sp3 hybridised and adopts a pyramidal geometry.
  • Bond angles are slightly less than tetrahedral (~108°) due to lone pair repulsion.
  • Based on substitution, amines are classified as 1° (primary), 2° (secondary), or 3° (tertiary).
  • Simple amines have identical groups and mixed amines have different substituents.

Full Notes

Amines are organic derivatives of ammonia in which one or more hydrogen atoms are replaced by alkyl or aryl groups.

Definition and Classification

Classification is based on the number of alkyl or aryl groups replacing hydrogen atoms in NH3:

Type General Formula Example
Primary (1°) R–NH2 Methylamine (CH3NH2)
Secondary (2°) R2NH
or
R–NHR′
Dimethylamine (CH3)2NH
Tertiary (3°) R3N or R2NR′ Trimethylamine (CH3)3N

If all substituents are the same = a simple amine

If different = a mixed amine

Molecular Structure and Hybridisation

The nitrogen atom in amines is trivalent and contains a lone pair.

NCERT Chemistry Class 12 Amines diagram showing pyramidal geometry at nitrogen with approximately 108° H–N–H bond angle due to lone pair repulsion.

It undergoes sp3 hybridisation, forming three sigma bonds and one lone pair.

This gives a pyramidal shape, similar to ammonia.

The bond angle is ~108°, slightly less than tetrahedral (109.5°) due to lone pair–bond pair repulsion.

Summary