pH Calculations, Ka and Kw
Quick Notes
- pH = –log[H⁺]
- [H⁺] = 10–pH
- Ka = [H⁺][A⁻] / [HA]
- pKa = –log Ka
- pKa is used to compare acid strength more conveniently
- Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴ mol² dm⁻⁶ at 298 K
- Strong acids: [H⁺] ≈ concentration of acid
- Strong bases: [OH⁻] ≈ concentration of base
- We can calculate [H⁺] in alkaline (basic) solutions using Kw
Full Notes
What is pH?
The pH scale measures the concentration of hydrogen ions (H⁺) in solution, on a logarithmic scale. This allows us to express a wide range of H⁺ concentrations more simply.

A lower pH indicates a higher concentration of hydrogen ions (i.e. a more acidic solution).
To work backwards and calculate [H+] from pH:

This is useful when you’re given a pH value and need to calculate the hydrogen ion concentration, such as in weak acid problems.
Strong Acids and pH
Strong acids fully dissociate in solution.
This means the concentration of hydrogen ions equals the concentration of the acid (for monoprotic acids such as HCl).
For Example Strong acid pH
For 0.01 mol dm⁻³ HCl:
[H⁺] = 0.01 mol dm⁻³
pH = –log(0.01) = 2.00
Because there's no equilibrium to consider, these pH calculations are straightforward.
Weak Acids and Ka
Weak acids only partially dissociate in solution, setting up an equilibrium:

The acid dissociation constant (Ka) is the equilibrium constant used for weak acid dissociation:

Where:
- [H⁺] and [A⁻] are concentrations of the dissociated ions
- [HA] is the concentration of the undissociated acid
The larger the Ka, the more the acid dissociates = stronger acid.
The smaller the Ka, the less it dissociates = weaker acid.
Introducing pKa
Ka values for weak acids are often very small, so it is sometimes easier to use pKa:

This is simply a more manageable number and a lower pKa = stronger acid.
You can also calculate Ka from pKa using:

Calculating pH of a Weak Acid
You can calculate the pH of a weak acid using its Ka value and its concentration.
Since weak acids partially dissociate with H⁺ and A⁻ in a 1:1 ratio, we assume:
- [H⁺] is approximately equal (≈) to [A⁻] (from HA dissociation)
- [HA] remains nearly unchanged
This means we can assume that [H⁺] × [A⁻] = [H⁺]².
![Edexcel A-Level Chemistry expression showing derivation of [H⁺] from Ka and [HA].](images/kaph.png)
Ka = ([H⁺]²) / [HA] and as a result [H⁺] = √(Ka × [HA]).
Steps to Calculate pH of a Weak Acid
- Use Ka expression:
Ka = ([H⁺]²) / [HA] - Rearrange to find [H⁺]:
[H⁺] = √(Ka × [HA]) - Find pH:
pH = –log[H⁺]


Don’t forget when using Ka to find the pH of a weak acid, we are assuming two things — one that [H⁺] = [A⁻] and that the [HA] at the start is the same as the concentration of weak acid at equilibrium. These are assumptions: for example the [HA] at equilibrium won’t be exactly the same as the initial [HA] as some will have dissociated, however the amount of dissociation is very small compared to the concentration meaning mathematically it isn’t significant enough for us to worry about.
Find the pH of 0.10 mol dm⁻³ ethanoic acid (Ka = 1.75 × 10⁻⁵).
- [H⁺] = √(Ka × [HA])
- [H⁺] = √(1.75 × 10⁻⁵ × 0.10) = 1.32 × 10⁻³ mol dm⁻³
- pH = –log(1.32 × 10⁻³) = 2.88
Using Experimental pH to Find Ka
You may be given the pH of a weak acid solution and asked to find Ka. Follow these steps:
- Convert pH to [H⁺]: [H⁺] = 10^(–pH)
- Assume [H⁺] = [A⁻]
- Use original acid concentration as [HA] (approximate)
- Plug into: Ka = [H⁺]² / [HA]
This is a common exam question.
A solution of a weak acid has a concentration of 0.100 mol dm⁻³ and a pH of 4.75. Calculate the Ka of the weak acid.
- Convert pH to [H⁺]: [H⁺] = 10^(–4.75) = 1.78 × 10⁻⁵ mol dm⁻³
- Assume [H⁺] = [A⁻] → [A⁻] = 1.78 × 10⁻⁵ mol dm⁻³
- Use original acid concentration as [HA] ≈ 0.100 mol dm⁻³
- Plug into Ka expression: (1.78 × 10⁻⁵)² / 0.100 = 3.17 × 10⁻⁹ mol dm⁻³
Final Answer: Ka = 3.17 × 10⁻⁹ mol dm⁻³
The Ionic Product of Water (Kw)
In water, a very small percentage of molecules ionise, releasing H⁺ and OH⁻ ions into solution.

This is a reversible process and an equilibrium is established.
The equilibrium constant for this is:

For a more detailed explanation on Kw and where it comes from, see here.
At 298 K: Kw = 1.0 × 10⁻¹⁴ mol² dm⁻⁶
Kw is key for finding pH of bases, because strong bases increase [OH⁻].
Calculating pH of Strong Bases
To calculate the pH of a strong base like NaOH:
- [OH⁻] = concentration of the base
- Use Kw to find [H⁺]
- Use [H⁺] to find pH
![Edexcel A-Level Chemistry worked example showing calculation of [H⁺] from [OH⁻] using Kw.](images/kwph1.png)
Find the pH of an NaOH solution with a concentration of 0.010 mol dm⁻³.
- [OH⁻] = 0.010
- [H⁺] = 1.0 × 10⁻¹⁴ / 0.010 = 1.0 × 10⁻¹²
- pH = –log(1.0 × 10⁻¹²) = 12.00
Using pKw
Just like Ka and pKa, we can define:

At 298 K, pKw = 14.
Summary
- pH measures hydrogen ion concentration using a logarithmic scale.
- Strong acids fully dissociate and weak acids partially dissociate with Ka the equilibrium constant.
- pKa is a convenient way to compare acid strengths (lower pKa = stronger acid).
- Kw links [H⁺] and [OH⁻] in water and at 298 K, Kw = 1.0 × 10⁻¹⁴.
- For weak acids, use Ka and concentration to calculate [H⁺] and pH.
- For strong bases, calculate [OH⁻], then find [H⁺] from Kw.
- pKw = 14 at 298 K.