Lattice Energy
Quick Notes
- Lattice energy (ΔLE) is the energy released when 1 mole of an ionic solid forms from its gaseous ions.
- A large negative lattice energy indicates strong bonding.
- Enthalpy change of atomisation (ΔHat) is the energy needed to form 1 mole of gaseous atoms from an element in its standard state.
- Electron affinity is the energy change when 1 mole of electrons is added to 1 mole of gaseous atoms.
- Born–Haber cycles can be used to find lattice energy using Hess's Law.
- A difference between experimental and theoretical lattice energies suggests covalent character.
- Polarising power of a cation increases with smaller radius and higher charge.
- Polarisability of an anion increases with larger radius and higher charge.
- Enthalpy change of solution (ΔHsol): the energy change when 1 mole of an ionic solid dissolves in water (to form an infinitely dilute solution).
- Enthalpy change of hydration (ΔHhyd): the energy released when 1 mole of gaseous ions dissolves in water (to form an infinitely dilute solution).
- Higher ionic charge and smaller ionic radius increase lattice and hydration enthalpies.
Full Notes
Lattice enthalpies and Born–Haber cycles have been outlined in more detail
here.
This page is just what you need to know for Edexcel A-level :)
Lattice energy (ΔHlatt) refers to the energy change associated with the formation of an ionic solid from its gaseous ions. It can be considered a measurement of the bonding strength in ionic compounds.

Lattice energies can’t be measured directly in an experiment however can be determined using experimental data with Hess’s Law.
Born–Haber cycles are a type of Hess cycle used to calculate lattice energy.
Key Definitions
Enthalpy change of atomisation (ΔHat):
The enthalpy change when 1 mole of gaseous atoms is formed from an element in its standard state.
Example Na(s) → Na(g)
Lattice energy (ΔHlatt):
The enthalpy change when 1 mole of an ionic solid is formed from its gaseous ions.
Example Na⁺(g) + Cl⁻(g) → NaCl(s)
Lattice energy is always exothermic (negative value).
Electron Affinity
- First electron affinity is the energy change when 1 mole of gaseous atoms gains electrons to form 1 mole of 1⁻ ions.
Example Cl(g) + e⁻ → Cl⁻(g)
This is usually exothermic. - Second electron affinity is for adding an electron to a negatively charged ion (e.g. O⁻ to O²⁻), and is endothermic due to repulsion.
Constructing a Born–Haber Cycle
- Write the enthalpy of formation equation (solid compound from elements).
- Convert elements to gaseous atoms (atomisation enthalpy).
- Remove electrons from metal atoms (ionisation energy).
- Add electrons to non-metal atoms (electron affinity).
- Combine gaseous ions to form lattice (lattice enthalpy).
Example Born–Haber Cycle for NaCl

- Step 1: Formation of NaCl (ΔHf)
Na(s) + ½Cl2(g) → NaCl(s) - Step 2: Atomisation of Na (ΔHatom)
Na(s) → Na(g) - Step 3: Atomisation of Cl2 (ΔHatom)
½Cl2(g) → Cl(g) - Step 4: Ionisation Energy of Na (IE1)
Na(g) → Na⁺(g) + e⁻ - Step 5: Electron Affinity of Cl (EA1)
Cl(g) + e⁻ → Cl⁻(g) - Step 6: Lattice Enthalpy (ΔHle)
Na⁺(g) + Cl⁻(g) → NaCl(s)
By rearranging these enthalpy changes and substituting experimental values into the cycle we can use Hess’s Law to calculate ΔHle.

Bond Strength from Lattice Energy
A more negative (larger magnitude) lattice energy means stronger electrostatic attraction between ions. This allows us to use lattice energies as a measure of bonding strength in ionic compounds.
Factors Affecting Lattice Energy
Charge and ionic radius affect the magnitude of lattice energy:
- Charge: Higher ion charge = stronger electrostatic attraction between ions = more exothermic lattice energy.
Example Mg²⁺ gives more exothermic lattice energies than Na⁺. - Ionic radius: Smaller radius = stronger attraction = more exothermic lattice energy.

Down a group, ionic radius increases and lattice energy becomes less exothermic.
Comparing Experimental vs. Theoretical ΔLE
Born–Haber cycle values come from experimental data, meaning lattice enthalpies from Born-Haber cycle calculations are called experimental lattice enthalpies.
Theoretical lattice enthalpy assumes purely ionic bonding based on perfectly spherical ions with a uniform charge. They are calculated using theoretical data about the ions (size and charge) in the compound.
If experimental values differ from theoretical values, the compound has some covalent character due to polarisation of the anion by the cation.
The greater the difference between experimental and theoretical values, the greater the degree of covalent character in the compound.
Polarisation and Ionic Radii
Cations with high charge and small radius have strong polarising power.
Anions with low charge density (large radius, high charge) are easily polarised.
This causes distortion of the electron cloud and introduces covalent character into the bond.
Example Covalent character in ionic lattices
- NaCl is nearly purely ionic (experimental ≈ theoretical).
- AgCl has a higher experimental lattice enthalpy than theoretical, indicating covalent character.

This can be explained by the fact Ag⁺ ions are able to polarise Cl⁻ ions more than Na⁺ ions. The Cl⁻ ion doesn’t remain a perfect sphere and there is a small amount of electron sharing between the two ions, meaning the bonding in the crystal isn’t purely ionic — hence the theoretical value which assumes only ionic bonding doesn’t match the actual, experimental value.
Solution and Hydration Enthalpies
Born–Haber cycles can also be used when dealing with enthalpies of solution and hydration.
Enthalpy of solution (ΔHsol):
The enthalpy change when 1 mole of an ionic compound dissolves in enough water to form an infinitely dilute solution.

Example NaCl(s) → Na⁺(aq) + Cl⁻(aq)
Enthalpy of hydration (ΔHhyd):
The enthalpy change when 1 mole of gaseous ions dissolves in water to form aqueous ions.

Example
Na⁺(g) → Na⁺(aq)
Cl⁻(g) → Cl⁻(aq)
Energy Cycle for Solution Enthalpy
An energy cycle can be constructed that links enthalpy of solution (ΔHsol), hydration enthalpies (ΔHhyd) and lattice energy (ΔHlatt):


For these energy cycles, the lattice energy is given as a positive value as the arrow direction is going from the ionic solid to the gaseous ions, this is breaking apart the lattice. This is the exact same value as lattice energy however it has a positive sign (+ΔH) rather than negative as it is an endothermic process.
Energy cycle equation:

- ΔHlatt is positive (energy needed to break lattice).
- ΔHhyd is negative (energy released when ions are hydrated).
Calculate ΔHsol, given:
- ΔHlatt (NaCl) = +769 kJ mol⁻¹
- ΔHhyd (Na⁺) = –406 kJ mol⁻¹
- ΔHhyd (Cl⁻) = –364 kJ mol⁻¹
Calculate ΔHsol: ΔHsol = +769 + (–406) + (–364)
ΔHsol = –1 kJ mol⁻¹
So, dissolving NaCl is slightly exothermic.
Factors Affecting Enthalpy of Hydration
The magnitude of ΔHhyd depends on:
- Ionic charge:
Higher charge = stronger attraction to water = more exothermic ΔHhyd.
Example Mg²⁺ has more negative ΔHhyd than Na⁺. - Ionic radius:
Smaller ions = stronger electrostatic attraction to water = more exothermic ΔHhyd.
Example Li⁺ is more exothermic than Cs⁺.
So, small, highly charged ions have more exothermic hydration enthalpies.
Summary
- Lattice energy is the energy released when 1 mole of an ionic solid forms from gaseous ions.
- Born–Haber cycles are used to calculate lattice energies from experimental data.
- Factors affecting lattice enthalpy: ionic charge and ionic radius.
- Difference between experimental and theoretical values suggests covalent character.
- Polarising power of cations and polarisability of anions introduce covalent character.
- Enthalpy of solution = lattice energy + hydration enthalpies.
- Hydration enthalpies are more exothermic for small, highly charged ions.