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*Revision Materials and Past Papers* 1 Atomic Structure and the Periodic Table 2 Bonding and Structure 3 Redox I 4 Inorganic Chemistry and the Periodic Table 5 Formulae, Equations and Amounts of Substance 6 Organic Chemistry I 7 Modern Analytical Techniques I 8 Energetics I 9 Kinetics I 10 Equilibrium I 11 Equilibrium II 12 Acid-base Equilibria 13 Energetics II 14 Redox II 15 Transition Metals 16 Kinetics II 17 Organic Chemistry II 18 Organic Chemistry III 19 Modern Analytical Techniques II RP Required Practicals

19 Modern Analytical Techniques II

19A Mass Spectrometry 19B Nuclear Magnetic Resonance (NMR) 19C Chromatography

Mass Spectrometry

Specification Reference Topic 19, points 1–6

Quick Notes

  • Mass spectrometry identifies organic compounds using mass-to-charge ratio (m/z) of ions from the compound.
  • The molecular ion peak (M⁺) gives the relative molecular mass (Mr).
  • Smaller peaks are caused by fragmentation – the breakdown of the molecular ion.
  • [M+1]⁺ peaks indicate the presence of carbon-13 isotopes.
  • [M+2]⁺ peaks reveal the presence of chlorine (3:1 ratio) or bromine (1:1 ratio) due to their isotopes.
  • Accurate mass data to 4 decimal places can differentiate between isomers or identify exact molecular formulae.

Full Notes

This builds on Mass Spectrometry as introduced in chapter 7 – here.

Mass Spectrometry – The Basics

Identifying Molecular Mass and Formula

The molecular ion peak (M⁺) has the highest m/z value on a spectra and we can use precise atomic masses to confirm the molecular formula.

Example:

Determining the molecular formula of a compound with M⁺ = 58.12

Edexcel A-Level Chemistry mass spectrum showing molecular ion peak at m/z 58.12 for C4H10 isomers.

Fragmentation

Inside the mass spectrometer, molecular ions can break into fragments. Each fragment forms a smaller ion and shows up as a peak at a lower m/z.

These peaks help identify parts of the molecule.

Example:

Hydrocarbons A and B both have formula C4H10. Their spectra differ due to fragmentation patterns.

Edexcel A-Level Chemistry mass spectra comparing C4H10 isomers showing fragmentation peaks. Edexcel A-Level Chemistry fragmentation pattern showing peak at m/z 29 indicating C2H5 group.

The extra peak at m/z 29 for Hydrocarbon B means it has a C2H5 group in its structure (as well as a CH3 and C3H7 group). This would indicate CH3CH2CH2CH33 as its structure.

The [M+1]⁺ Peak

This is a small peak 1 unit higher than M⁺, caused by molecules containing one carbon-13 atom.

Edexcel A-Level Chemistry mass spectrum showing M+1 peak caused by C-13 isotopes.

The [M+2]⁺ Peak – Identifying Cl and Br

Organic compounds that contain chlorine or bromine show an M+2 peak due to isotopes:

This is because chlorine and bromine both have isotopes that differ by a mass number of 2 (Cl-35 and Cl-37 and Br-79 and Br-81).

For example:
The mass spectra for chloromethane shows an M+2 peak. The main molecular ion peak is at 50 (contains the Cl-35 isotope) and 52 (contains the Cl-37 isotope).

Edexcel A-Level Chemistry spectrum for chloromethane showing M and M+2 peaks in 3:1 ratio.

Using Accurate Mass Data

High-resolution mass spectrometers measure Mr accurate to 4 decimal places, allowing precise determination of molecular formula.

Worked Example: Determining a Molecular Formula from Mass Spectra

Both C3H8O and C2H4O2 have a relative molecular mass (Mr) of 60, but differ in exact mass. In a mass spectrum, the M+ peak of the compound is at 60.0575. Using the following relative atomic masses, determine the molecular formula of the compound.

  • C = 12.0000
  • H = 1.0078
  • O = 15.9949

For C3H8O:
(3 × 12.0000) + (8 × 1.0078) + (1 × 15.9949) = 60.0575 → MATCH

For C2H4O2:
(2 × 12.0000) + (4 × 1.0078) + (2 × 15.9949) = 60.0210 → doesn’t match

Conclusion: The compound could be propanol but not ethanoic acid.