Core Practical 3 – Find the Concentration of Hydrochloric Acid
Aim: To determine the concentration of a hydrochloric acid solution by titrating it against a standard solution of sodium hydroxide.
Chemical Equation
Balanced Equation:
HCl + NaOH → NaCl + H₂O
This is a 1:1 molar ratio reaction between a strong acid and a strong base.
Apparatus and Chemicals
Equipment:
- Burette, clamp and stand
- 25 cm³ pipette and safety filler
- 250 cm³ volumetric flask
- 250 cm³ conical flask
- 100 cm³ and 250 cm³ beakers
- Funnel
- Distilled and deionised water
Chemicals:
- Standard sodium hydroxide solution (~0.08 mol dm⁻³)
- Hydrochloric acid of unknown concentration
- Phenolphthalein indicator
Safety Notes
- Wear goggles throughout the experiment.
- Phenolphthalein is flammable and toxic.
- Hydrochloric acid is an irritant – avoid contact with skin.
- Fill burettes below eye level to avoid splashes.
Procedure
Prepare the solution for titration:
- Wash out a 250 cm³ volumetric flask with distilled water.
- Use a pipette to transfer exactly 25.0 cm³ of the unknown HCl solution into the flask.
- Fill the flask to the mark with deionised water – this dilutes the acid to a known volume.
Set up titration equipment:
- Fill a burette with standard sodium hydroxide solution.
- Place 25.0 cm³ of the diluted hydrochloric acid in a conical flask using a clean pipette.
Add indicator:
- Add 2 drops of phenolphthalein – the solution should remain colourless (acidic).
Titrate:
- Slowly add NaOH from the burette while swirling.
- The endpoint is reached when the solution turns pale pink and stays pink for at least 5 seconds.
- Record the initial and final burette readings to the nearest 0.05 cm³.
- Repeat until you obtain two concordant titres (within 0.10 cm³).
- Record results in a table.
Sample Data
| Trial | Final (cm³) | Initial (cm³) | Titre (cm³) |
|---|---|---|---|
| 1 | 30.55 | 0.45 | 30.10 |
| 2 | 32.10 | 2.15 | 29.95 |
| 3 | 30.65 | 0.60 | 30.05 |
| 4 | 33.40 | 3.15 | 30.25 |
Analysis of Results
- Mean titre (use concordant values only)
Example: Mean = (30.05 + 29.95) / 2 = 30.00 cm³ - Moles of NaOH in mean titre
Suppose [NaOH] = 0.080 mol dm⁻³
Volume = 30.00 cm³ = 0.03000 dm³
Moles = 0.080 × 0.03000 = 0.00240 mol - Moles of HCl in 25.0 cm³ aliquot
Ratio is 1:1, so moles HCl = 0.00240 mol - Moles in full 250 cm³ solution
= 0.00240 × 10 = 0.0240 mol - Concentration of original HCl
c = n / V = 0.0240 / 0.025 = 0.96 mol dm⁻³
Matt’s Exam Tip
Do not include the rough titration when calculating your mean.
Record all burette readings to the nearest 0.05 cm³.
Consistent swirling between adding drops from burette prevents overshooting the endpoint.
Common Errors and Considerations
- Phenolphthalein may fade after turning pink due to reaction with atmospheric CO₂ (forming carbonic acid).
- Best titre volume is around 25–30 cm³; too small and percentage errors increase.