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*Revision Materials and Past Papers* 1 Atomic Structure and the Periodic Table 2 Bonding and Structure 3 Redox I 4 Inorganic Chemistry and the Periodic Table 5 Formulae, Equations and Amounts of Substance 6 Organic Chemistry I 7 Modern Analytical Techniques I 8 Energetics I 9 Kinetics I 10 Equilibrium I 11 Equilibrium II 12 Acid-base Equilibria 13 Energetics II 14 Redox II 15 Transition Metals 16 Kinetics II 17 Organic Chemistry II 18 Organic Chemistry III 19 Modern Analytical Techniques II RP Required Practicals

14 Redox II

14.1 Redox Fundamentals and Oxidation Numbers 14.2 Standard Electrode Potentials 14.3 Electrochemical Cells and Cell Potentials 14.4 Applications of Electrode Potentials 14.5 Redox Titrations

Electrochemical Cells and Cell Potentials

Specification Reference Topic 14, points 7–14

Quick Notes

  • Standard Cell Potential (E°cell)
    • Overall voltage from two half-cells under standard conditions.
    • cell = E°(cathode) − E°(anode).
    • Cathode = more positive E°, anode = more negative E°.
  • Electron Flow and Reaction Feasibility
    • Electrons flow from anode to cathode.
    • Positive E°cell = forward reaction feasible.
    • Negative E°cell = reverse reaction favoured.
  • Reactivity Trends from E° Values
    • Higher E° = stronger oxidising agent.
    • Lower E° = stronger reducing agent.
  • cell predicts feasibility: a positive value suggests a reaction is feasible.
  • cell relates to entropy and the equilibrium constant:
    ΔG° = −RT ln K
    • Greater E°cell = larger total entropy change (+ΔStotal)
    • Greater E°cell = larger K (forward direction favoured)

Full Notes

The background theory of electrochemical cells and half-cells for Edexcel A-level chemistry is covered here.

The standard cell potential is the overall voltage produced when two half-cells are connected under standard conditions.

It’s calculated by:

Edexcel A-Level Chemistry formula sheet panel showing E°cell equals E°cathode minus E°anode under standard conditions.

Note:

Meaning you can also write this as:

Edexcel A-Level Chemistry alternative expression of E°cell as E°(reduction) minus E°(oxidation).
Worked Example

Determine the Ecell when the following two half-cells are connected together:

  • Zn2+(aq) + 2e ⇌ Zn(s)  E° = –0.76 V
  • Cu2+(aq) + 2e ⇌ Cu(s)  E° = +0.34 V

Here, Cu2+/Cu will be the cathode (reduction), and Zn2+/Zn will be the anode (oxidation).

cell = (+0.34) − (−0.76) = +1.10 V

Cell Notation

In electrochemistry, cells are written using a shorthand:

For example Write the conventional cell notation for an electrochemical cell made from the following:

Zn²⁺(aq) + 2e⁻ ⇌ Zn(s)  E° = −0.76 V
Cu²⁺(aq) + 2e⁻ ⇌ Cu(s)  E° = +0.34 V

We’ve already established (see above) Cu²⁺/Cu is the cathode, where reduction happens. Cu²⁺ will be reduced to Cu. Equally, Zn²⁺/Zn is the anode, where oxidation happens, Zn will be oxidised to Zn²⁺.

Anode is written on the left with the Zn(s) and Zn²⁺(aq) separated by a vertical line as they are in different phases. Cathode is written on the right with the Cu²⁺(aq) and Cu(s) again separated by a vertical line.

Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s)

Edexcel A-Level Chemistry conventional cell notation and annotated sketch for Zn(s)|Zn²⁺(aq)||Cu²⁺(aq)|Cu(s).

Predicting Thermodynamic Feasibility

The link between feasibility, the equilibrium constant K and electrochemical cells has been outlined in detail here. However, on this page is just what you need to know for Edexcel A-level, don’t worry too much about the extra background - just learn the equations and practice using them :)

You can predict whether a redox reaction is feasible (able to happen) using the calculated standard cell potential:

Edexcel A-Level Chemistry reminder graphic for calculating E°cell to assess feasibility.

If E°cell is positive, the reaction is thermodynamically feasible under standard conditions.

However, a feasible reaction may not happen due to kinetic barriers like high activation energy.

Link to Entropy and Equilibrium Constant

Gibbs free energy change relates to the cell potential:

Edexcel A-Level Chemistry relationship between ΔG°, nF and E°cell for electrochemical cells.

Where:

If ΔG° is negative, the reaction is spontaneous.

So if E°cell is large and positive, ΔG is large and negative.

This means the forward direction (production of products) of the reaction is favoured, giving a large equilibrium constant, K.

ΔG° and K (Equilibrium Constant) are linked by:

Edexcel A-Level Chemistry equation panel showing ΔG° = −RT ln K linking thermodynamics and equilibrium.

Limitations of E° Predictions

Even if E°cell suggests a reaction is feasible, the following factors may prevent it:

So, a reaction predicted as feasible might not occur in practice, or might proceed only very slowly.

Electrochemical Series

The electrochemical series is a list of half-cells arranged in order of increasing E° values:

Edexcel A-Level Chemistry electrochemical series ordering half-cells by standard electrode potential.

The series helps us predict which species will be oxidised or reduced in a reaction.

Disproportionation Reactions

In a disproportionation reaction, one species is both oxidised and reduced.

These reactions are likely when:

Worked Example: Disproportionation of Chlorine in Water

Reaction: Cl2 + H2O → HCl + HClO

Step 1: Reduction half-equation (chlorine → chloride)

Cl2 + 2e → 2Cl     E° = +1.36 V

This shows chlorine is reduced to chloride ions.

Step 2: Oxidation half-equation (chlorine → chlorate(I))

Cl2 + H2O → ClO + 2H+ + e     (reverse of reduction E° ≈ +1.63 V)

Here chlorine is oxidised, forming chlorate(I) ions (ClO).

Step 3: Comparison with water redox couple

O2(g) + 4H+ + 4e ⇌ 2H2O(l)     E° = +1.23 V

This provides a reference point: chlorine has a higher potential than water, so it is more easily reduced but can also act as an oxidising agent strong enough to oxidise itself.

Step 4: Explanation

Chlorine sits between these two potentials: it has a higher reduction potential than water (+1.36 V vs +1.23 V), so it is readily reduced to Cl. But chlorine can also be oxidised to ClO, because the Cl2/ClO couple has a higher potential than Cl2/Cl. Being able to both oxidise and reduce itself explains why chlorine undergoes disproportionation in water.

Summary