Buffers and Their Action
Quick Notes
- A Buffer solution resists pH change when small amounts of acid or base are added to it.
- Buffers are typically made by:
- Mixing a weak acid and its conjugate base (e.g. ethanoic acid + sodium ethanoate)
- Mixing Excess weak acid with strong base, forming some salt in situ.
- Acidic buffers maintains equilibrium:
HA ⇌ H+ + A−- If acid (H+) is added: A− removes it by forming more HA.
- If base (OH−) is added: HA donates H+ to neutralise OH−.
- Buffers are important in biological, industrial, and laboratory settings.
- In blood: carbonic acid–hydrogencarbonate buffer maintains pH ~7.4.
Full Notes
Buffers and calculations have been outlined in more detail here.
This page is just what you need to know for Edexcel A-level :)
A buffer solution maintains a relatively constant pH despite the addition of small amounts of acid or base. They ‘minimise’ change to pH.
Buffers are essential in biological systems and many industrial processes where a near constant pH is important. For example, in living organisms buffers maintain an optimum pH to prevent enzymes from being denatured.
Types of Buffers:
Acidic Buffers:
Made from a weak acid and its salt (that contains the acids conjugate base).
For example The weak acid ethanoic acid (CH3COOH) and its salt sodium ethanoate (CH3COONa).

When added to a solution of the ethanoic acid, the CH3COONa would dissociate and release CH3COO− ions, which is the conjugate base (A−) of the ethanoic acid.
Basic Buffers:
Made from a weak base and its salt (that contains the conjugate acid of the base).
For example The weak base ammonia (NH3) and its salt ammonium chloride (NH4Cl).

When added to a solution of ammonia, the NH4Cl would dissociate and release NH4+ ions, which are the conjugate acid ions of the ammonia.
How Acidic Buffers Work
An equilibrium is established in the buffer system between HA, A− and H+.

The concentration of HA and A− in the mixture must be much greater than the concentration of H+. This ensures the position of equilibrium is sensitive to changes in H+ concentration change more than changes to HA and A− concentration. Equilibrium position can shift to keep H+ ion concentration nearly constant.
Example: Ethanoic Acid/Sodium Ethanoate Buffer
CH3COOH ⇌ H+ + CH3COO−
When an acid (H+) is added:

- CH3COO− combines with added H+ to form CH3COOH.
- Equilibrium shifts left, reducing the increase in H+. [HA] increases and [A−] decreases.
When a base (OH−) is added:

- Added OH− reacts with H+ to form H2O.
- CH3COOH dissociates more to replace lost H+.
- Equilibrium shifts right, replacing H+ ions that reacted with the added OH−, resisting pH increase. [HA] decreases and [A−] increases.

Remember that the concentration of HA and A- will change when H+ or OH- ions are added. When H+ ions are added to the mixture - the moles of HA will increase by the same as the moles of H+ added and moles of A- decrease by the same amount. When OH- ions are added - the moles of HA will decrease by the same as moles of OH- added and the moles of A- increase by the same amount.
Q: What happens to the pH when a small amount of NaOH is added to a buffer made of 0.10 mol dm-3 CH3COOH and 0.10 mol dm-3 CH3COO−?
- Set up & assumptions
Take 1.00 dm3 of buffer so initial moles are CH3COOH (HA) = 0.10 mol and CH3COO− (A−) = 0.10 mol. Add 0.010 mol NaOH (small amount). Assume volume change is negligible. - Neutralisation reaction (stoichiometry)
OH− + HA → A− + H2O
New moles: HA = 0.10 − 0.010 = 0.090 mol; A− = 0.10 + 0.010 = 0.110 mol; OH− is fully consumed. - pH before addition (use the Ka expression)
For ethanoic acid, Ka = 1.75 × 10−5 mol dm−3.
Ka = \[\,[H+][A−] / [HA]\,\] ⇒ [H+] = Ka × [HA]/[A−].
With [HA] = [A−] = 0.10 mol dm-3, [H+] = 1.75 × 10−5 mol dm-3.
pH = −log(1.75 × 10−5) = 4.76. - pH after addition (again from Ka)
[HA] ≈ 0.090 mol dm-3; [A−] ≈ 0.110 mol dm-3 (total volume 1.00 dm3).
[H+] = Ka × ([HA]/[A−]) = 1.75 × 10−5 × (0.090/0.110) = 1.43 × 10−5 mol dm-3.
pH = −log(1.43 × 10−5) ≈ 4.84.
A: The added OH− reacts with CH3COOH:
CH3COOH + OH− → CH3COO− + H2O.
CH3COOH decreases to 0.090 mol dm-3 and CH3COO− increases to 0.110 mol dm-3. Using the equilibrium expression for Ka, the pH changes only slightly: 4.76 → 4.84 (ΔpH ≈ +0.08), demonstrating buffer action.
How Basic Buffers Work
Basic buffers follow the same principle as for acidic buffers, with a position of equilibrium shifting to oppose a change in pH. This time however it's the OH− ion concentration that the equilibrium is sensitive to.
Example Ammonia/Ammonium Chloride Buffer (NH3/NH4+)
Equilibrium reaction: NH3 + H2O ⇌ NH4+ + OH−
When an acid (H+) is added:
- H+ reacts with OH− to form H2O.
- Equilibrium shifts right, with more NH3 reacting with H2O to replace OH− ions, meaning pH decrease is reduced.
When a base (OH−) is added:
- NH4+ reacts with added OH− to form NH3 and H2O.
- Equilibrium shifts left, reducing pH increase.
Buffers in Titration Curves
In a weak acid + strong base titration:

- Before the equivalence point, both HA and A− are present, forming a buffer system.
- The pH changes only minimally as base is added, however when the concentration of HA falls too low, the mixture is no longer able to act as a buffer and the pH changes rapidly as more base is added.
Buffers in Blood
Blood pH is controlled by a hydrogencarbonate buffer system:
H2CO3 ⇌ H+ + HCO3−
- If H+ is increased then HCO3− removes H+, forming H2CO3.
- If OH− is added then H2CO3 releases H+, neutralising the OH−.
This maintains blood pH around 7.4.
Summary
- Buffers resist pH change by having significant amounts of HA and A− (or base and its conjugate acid) present.
- Acidic buffers: weak acid plus its salt and basic buffers: weak base plus its salt.
- Added H+ is removed by A−; added OH− is neutralised by HA.
- Buffer pH can be calculated from Ka, [HA], and [A−].
- Buffer regions appear before equivalence in weak acid–strong base titrations.
- The hydrogencarbonate buffer maintains blood pH near 7.4.