Core Practical 14: Determine Activation Energy (Arrhenius Experiment)
Objective: To determine the activation energy (Ea) for a reaction using the Arrhenius equation by measuring the rate of reaction at different temperatures.
Reaction Summary
Overall reaction:
C6H5OH + 3Br2 → C6H2Br3OH + 3HBr
The bromine is generated in situ from bromate(V) and bromide ions in acidic solution.
Indicator reaction: Once phenol is used up, excess Br2 reacts with methyl red, causing a colour change (disappearance of colour), which marks the endpoint.
Safety Notes
- Phenol is corrosive and toxic – wear gloves and use in a fume cupboard.
- Sulfuric acid is an irritant.
- Potassium bromate(V) is an oxidising agent.
- Wear eye protection, lab coat, and conduct a risk assessment.
Apparatus and Chemicals
- 0.01 mol dm⁻³ phenol solution
- Mixed bromide/bromate solution:
- 0.1 mol dm⁻³ KBr
- 0.02 mol dm⁻³ KBrO₃
- 0.5 mol dm⁻³ sulfuric acid
- Methyl red indicator
- 2 boiling tubes, pipettes, beakers
- Water bath or kettle, thermometer (0–110 °C), stop clock
Procedure

- Prepare hot water bath (start at 75 °C).
- Pipette 10 cm³ of phenol solution and 10 cm³ of bromide/bromate solution into a boiling tube.
- Add 4 drops of methyl red.
- In a second boiling tube, pipette 5 cm³ sulfuric acid.
- Place both tubes into the water bath until they reach temperature.
- Mix both solutions by transferring them quickly between the tubes. Start timing.
- Leave the tube in the bath. Stop timing when the methyl red colour disappears.
- Repeat for other temperatures: 65, 55, 45, 35, 25, and 15 °C. Use ice for the lowest temperature if required.
Table to Record Results
Temperature (°C) | Temperature (K) | Time for Colour Disappearance (s) | 1/T (K⁻¹) | ln(t) |
---|---|---|---|---|
75 | 348 | example: 32 | 0.00287 | 3.47 |
65 | 338 | – | – | – |
55 | 328 | – | – | – |
45 | 318 | – | – | – |
35 | 308 | – | – | – |
25 | 298 | – | – | – |
15 | 288 | – | – | – |
Calculations and Graphing
- Convert °C to K by adding 273.
- Calculate 1/T and ln(t).
- Plot a graph of ln t (y-axis) against 1/T (x-axis).
- The gradient (m) of this graph = Ea / R.
- Rearrange: Ea = gradient × R (R = 8.314 J mol⁻¹ K⁻¹).
