Bond Enthalpies
Quick Notes
- Bond Enthalpy: Energy to break 1 mole of bonds in the gaseous state.
- Breaking bonds is endothermic (ΔH is positive, energy absorbed).
- Making bonds is exothermic (ΔH is negative, energy released).
- Mean bond enthalpy: average energy required to break a particular type of bond across different compounds.
- Use mean bond enthalpies to estimate enthalpy changes:
- ΔH = Σ(Bond enthalpies of bonds broken) − Σ(Bond enthalpies of bonds formed)
Full Notes
Bond Enthalpies
Average (or mean) bond enthalpy is the average energy required to break 1 mole worth of a given bond type in gaseous molecules.
They are calculated using different molecules that have that bond type in.
Example: The C–H bond has a mean bond enthalpy of +412 kJ mol−1. However, the exact bond enthalpy of a C–H bond will vary slightly depending on the specific molecule it is in.
Breaking bonds requires energy = Endothermic process (ΔH is positive).
Making bonds releases energy = Exothermic process (ΔH is negative).
Example:
Breaking H–H bond: H2(g) → 2H(g), ΔH = +436 kJ mol−1
Forming H–H bond: 2H(g) → H2(g), ΔH = −436 kJ mol−1
Calculating Enthalpy Change Using Bond Enthalpies
The enthalpy change of a reaction can be estimated using:
Where:
- Bonds broken (in reactants) = Energy absorbed (endothermic, +ΔH).
- Bonds formed (in products) = Energy released (exothermic, -ΔH).
Note: Calculations using mean bond enthalpies are estimates and may differ from experimental values.
Remember bond enthalpies are for substances in the gaseous state. Always check that all species are in gaseous phase when doing bond enthalpy calculations – sometimes enthalpy of vaporisation must be used first.
Calculate the enthalpy change (ΔH) for the combustion of methane, using given bond enthalpies:
- C–H = +412 kJ mol−1
- O=O = +498 kJ mol−1
- C=O = +805 kJ mol−1
- O–H = +463 kJ mol−1
- Bonds Broken (Reactants - Energy Absorbed)
Bonds in CH4: 4 × C–H = 4 × 412 = 1648 kJ
Bonds in O2: 2 × O=O = 2 × 498 = 996 kJ
Total energy to break bonds = 1648 + 996 = 2644 kJ - Bonds Formed (Products - Energy Released)
Bonds in CO2: 2 × C=O = 2 × 805 = 1610 kJ
Bonds in H2O: 4 × O–H = 4 × 463 = 1852 kJ
Total energy released = 1610 + 1852 = 3462 kJ - Calculate Enthalpy Change
ΔH = Bonds broken − Bonds formed
ΔH = 2644 − 3462
ΔH = −818 kJ mol−1 (exothermic reaction)
Summary
- Bond enthalpy is the energy required to break 1 mole of bonds in the gaseous state.
- Breaking bonds is endothermic, while making bonds is exothermic.
- Mean bond enthalpies allow estimation of enthalpy changes.
- Calculations are approximate and less accurate than experimental methods.