Redox
Quick Notes
- Oxidising agent: gains electrons (is reduced)
- Reducing agent: loses electrons (is oxidised)
- We can use oxidation numbers to see if a redox reaction occurs
- Half-equations show individual oxidation or reduction steps
- Oxidation: electrons lost, e.g. Mg → Mg2+ + 2e−
- Reduction: electrons gained, e.g. Cl2 + 2e− → 2Cl−
- Use H+ and H2O in acidic solutions to balance O and H
- Add H2O to balance O atoms
- Add H+ to balance H atoms
- Add e− to balance charge
- Example: 8H+ + MnO4− + 5e− → Mn2+ + 4H2O (acidic reduction of MnO4−)
- Combining Half-Equations
- Balance electrons in oxidation and reduction equations
- Add together → electrons cancel out
- Example:
- Mg → Mg2+ + 2e−
- Cl2 + 2e− → 2Cl−
- Final: Mg + Cl2 → MgCl2
- Predicting Redox Feasibility
- A redox reaction occurs if:
- Stronger reducing agent donates e−
- Stronger oxidising agent accepts e−
- Example: Zn + Cu2+ → Zn2+ + Cu (reaction occurs).
Cu + Zn2+ → no reaction.
Full Notes
Oxidising and Reducing Agents
Oxidising agent: accepts electrons and becomes reduced.
Reducing agent: donates electrons and becomes oxidised.
Use changes in oxidation number to identify what is being oxidised and reduced.
What Are Ionic Half-Equations?
Half-equations allow us to show oxidation and reduction steps separately.
- Each redox reaction has two half-equations:
- One showing oxidation (loss of electrons)
- One showing reduction (gain of electrons)
- Electrons (e−) are included to show the movement of charge.
Writing Half-Equations
- Oxidation → electrons are lost, written on the right:
Mg → Mg2+ + 2e−
- Reduction → electrons are gained, written on the left:
Cl2 + 2e− → 2Cl−
Always remember that half equations don’t occur on their own; they’re a tool to represent just the oxidation or reduction part of a redox reaction, focusing only on the species gaining or losing electrons and ignoring everything else.
When to Use H+ and H2O in Half-Equations
In aqueous solutions, particularly under acidic conditions, when writing redox reactions we sometimes also include other ions such as H+ and H2O. This enables us to balance atoms and charges.
- Add H2O to balance oxygen atoms
- Add H+ to balance hydrogen atoms (can use OH− in alkaline conditions)
Example: Acidic Reduction of Manganate(VII) Ions (MnO4− → Mn2+)
Unbalanced reaction: MnO4− → Mn2+
Balance Mn atoms (already 1 on each side)
Balance O using H2O – add 4H2O to right: MnO4− → Mn2+ + 4H2O
Balance H using H+ – add 8H+ to left: 8H+ + MnO4− → Mn2+ + 4H2O
Balance charge with e− – add 5e− to left: 8H+ + MnO4− + 5e− → Mn2+ + 4H2O
Constructing Redox Equations
To form a full redox equation:
- Write both half-equations
- Balance electrons
- Add the two equations together so electrons cancel out
Example: Reaction of magnesium with chlorine
Half-equations:
Mg → Mg2+ + 2e−
Cl2 + 2e− → 2Cl−
Add together: Mg + Cl2 → MgCl2
Electrons cancel (2e− lost = 2e− gained)
Predicting Electron Transfer Reactions
Reactions occur if a stronger oxidising agent meets a stronger reducing agent.
Example: If Zn is mixed with Cu2+, a reaction will occur. Zn will be oxidised (lose 2e−) and Cu2+ will be reduced (gain 2e−), because Zn is a more powerful reducing agent than Cu.
Example: If Cu is mixed with Zn2+, no reaction will occur. Cu is unable to reduce Zn2+ as it is a weaker reducing agent than Zn.
Summary
- Oxidising agents gain electrons and are reduced, reducing agents lose electrons and are oxidised.
- Half-equations show individual oxidation and reduction steps.
- Balance half-equations with H+, H2O, and e− as needed.
- Redox equations are built by combining half-equations and cancelling electrons.
- A reaction is feasible if a stronger reducing agent reacts with a stronger oxidising agent.