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*Revision Materials and Past Papers* 1 Atomic Structure 2 Amounts of Substance 3 Bonding 4 Energetics 5 Kinetics 6 Chemical Equilibria & Kc 7 Redox Equations 8 Thermodynamics 9 Rate Equations 10 Kp (Equilibrium Constant) 11 Electrode Potentials & Cells 12 Acids and Bases 13 Periodicity 14 Group 2: Alkaline Earth Metals 15 Group 7: The Halogens 16 Period 3 Elements & Oxides 17 Transition Metals 18 Reactions of Ions in Aqueous Solution 19 Intro to Organic Chemistry 20 Alkanes 21 Halogenoalkanes 22 Alkenes 23 Alcohols 24 Organic Analysis 25 Optical Isomerism 26 Aldehydes & Ketones 27 Carboxylic Acids & Derivatives 28 Aromatic Chemistry 29 Amines 30 Polymers 31 Amino Acids, Proteins & DNA 32 Organic Synthesis 33 NMR Spectroscopy 34 Chromatography RP1–RP12 Required Practicals

1.2 Amounts of Substance

1.2.1 Relative Atomic Mass and Relative Molecular Mass 1.2.2 The Mole and the Avogadro Constant 1.2.3 The Ideal Gas Equation 1.2.4 Empirical and Molecular Formulae 1.2.5 Balanced Equations and Atom Economy

Balanced Equations, Atom Economy, and Percentage Yield

Specification Reference Physical Chemistry, Amount of Substance 3.1.2.5

Quick Notes

  • Balanced Equations ensure that the number of moles of each atom of each element remains the same on both sides of a reaction.
  • Atom Economy (%) measures the efficiency of a reaction based on relative molecular masses of reactants and products:
    AQA A‑Level Chemistry formula card showing Percentage Atom Economy equals Mr of desired product over total Mr of all reactants times 100.
  • Percentage Yield (%) measures how much product is obtained compared to the theoretical maximum amount:
    AQA A‑Level Chemistry formula card showing Percentage Yield equals actual yield divided by theoretical yield times 100.
  • High atom economy and high percentage yield are desirable in industry to maximise efficiency and reduce waste.

Full Notes:

Understanding Balanced Equations

Balanced equations ensure that the law of conservation of mass is obeyed – no atoms are lost or created during a reaction.

Steps to Balance a Chemical Equation

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Matt’s exam tip

It's important to understand that balanced equations show molar ratios.
For example, 0.5Cl2 means 0.5 moles worth of Cl2, it doesn't mean half a Cl2 molecule.


Worked Example: Balancing a Simple Equation

Unbalanced: H2 + O2 → H2O

  1. There are 2 moles of oxygen atoms in O2 but only 1 in H2O.
  2. To balance oxygen, place 2 moles of H2O molecules on the right: H2 + O2 → 2H2O
  3. Now there are 4 moles of hydrogen atoms on the right, so we need 2 moles of H2 molecules on the left: 2H2 + O2 → 2H2O

Balanced Equation: 2H2 + O2 → 2H2O

Understanding Atom Economy

Atom economy is a measure of a reactions efficiency - how much of the reactants end up as the desired product rather than waste.

Atom economy is theoretical - it is based only on the balanced reaction equation it isn’t based on experimental data.

Formula for Atom Economy:

AQA A‑Level Chemistry formula card: Percentage Atom Economy equals Mr of desired product over total Mr of all reactants times 100.
Worked Example : Calculating Atom Economy

Find the percentage atom economy for the production of Iron (Fe) from the reaction between Iron (III) Oxide and Carbon Monoxide.

AQA A‑Level Chemistry worked example calculating atom economy for Fe from Fe2O3 and CO, giving 45.8%.

If there is only one product in the reaction, then the atom economy must be 100%. For example, Find the percentage atom economy for the production of ethanol (CH3CH2OH) from the reaction between ethene (CH2CH2) and water (H2O).

AQA A‑Level Chemistry worked example showing 100% atom economy for making ethanol from ethene and water.

This reaction is 100% atom efficient because all reactants are converted into the desired product.

Understanding Percentage Yield

Percentage yield compares the actual amount of product obtained to the maximum possible amount (theoretical yield).

Unlike atom economy, percentage yield is calculated using experimental (actual) data.

Formula for Percentage Yield

AQA A‑Level Chemistry formula card: Percentage Yield equals actual yield divided by theoretical yield times 100.

Actual yield = Mass of product obtained in an experiment.
Theoretical yield = Maximum amount of product predicted by the balanced equation.

Photo of Matt
Matt’s exam tip

Matt’s Exam Tip - Remember that atom economy is theoretical and based on the balanced reaction equation whereas percentage yield is experimental and based on actual experimental data - it can’t be determined before a reaction has happened.

Steps to Calculate Percentage Yield

Worked Example: Simple Percentage Yield Calculation

In the reaction: Mg + 2HCl → MgCl2 + H2, if 2.40 g of Mg is reacted with excess HCl, and only 5.80 g of MgCl2 is obtained, what is the percentage yield?

AQA A‑Level Chemistry worked example showing percentage yield calculation for Mg + 2HCl → MgCl2 + H2 giving 61.7%.

Why Percentage Yield is always Less Than 100%

In reality, percentage yields are rarely 100% because of:

Industrial Importance of Atom Economy and Percentage Yield

Summary