Aldehydes and Ketones
Quick Notes
- Aldehydes can be oxidised to carboxylic acids using oxidising agents such as acidified potassium dichromate (K2Cr2O7/H2SO4).
- Aldehydes can be identified using:
- Fehling’s solution (blue solution to brick red precipitate)
- Tollens’ reagent (silver precipitate forms - silver mirror).
- Ketones don’t give a result with either.
- Aldehydes reduce to primary alcohols, and ketones reduce to secondary alcohols using NaBH4 (nucleophilic addition).
- Carbonyl compounds react with KCN followed by dilute acid to form hydroxynitriles, potentially forming enantiomers.
Full Notes
Oxidation of Aldehydes
Aldehydes can be oxidised to carboxylic acids by an oxidising agent such as acidified potassium dichromate (K2Cr2O7/H2SO4).
Ketones do not undergo oxidation under normal conditions.
Observation: Orange K2Cr2O7 turns green (Cr2O72- ions are reduced to green Cr3+ ions).
Equation for aldehyde oxidation:
CH3CHO + [O] → CH3COOH

Distinguishing Aldehydes and Ketones
Aldehydes can be further oxidised to carboxylic acids.
Ketones cannot be further oxidised.
Fehling’s Test:
Reagent: Fehling’s solution (contains Cu2+ ions).

Aldehyde result: Brick-red precipitate (Cu2O formed).
Ketone result: No visible change.
Tollens’ Test:
Reagent: Tollens’ reagent ([Ag(NH3)2]+ complex).

Aldehyde result: Silver mirror (Ag precipitate forms).
Ketone result: No visible change.
Reduction of Aldehydes and Ketones (Nucleophilic Addition)

Remember in organic chemistry that oxidation is the gaining of a bond to a more electronegative element (such as oxygen or nitrogen) and, or the loss of a bond to a less electronegative element (hydrogen).
Reduction is the opposite of this - the losing of a bond to a more electronegative element (such as oxygen or nitrogen) and the gaining of a bond to hydrogen.
[H] in reactions represents the addition of hydrogen, indicating a reduction reaction. It is often used as shorthand for a reducing agent, such as sodium borohydride (NaBH4) when reducing carbonyls.
Aldehydes can be reduced to primary alcohols.
Reagent: NaBH4 in aqueous solution.

Equation for aldehyde reduction:
CH3CHO + 2[H] → CH3CH2OH
Ketones can be reduced to secondary alcohols.
Reagent: NaBH4 in aqueous solution.

Equation for ketone reduction:
CH3COCH3 + 2[H] → CH3CH(OH)CH3
Mechanism
The reduction reactions for both aldehydes and ketones follow a nucleophilic addition mechanism, with the nucleophile a hydride ion (H−) coming from the NaBH4.

Reaction with KCN to Form Hydroxynitriles (Nucleophilic Addition)
Aldehydes and ketones react with KCN followed by dilute acid to form hydroxynitriles.
Reagent: KCN followed by H+.
Mechanism: Nucleophilic addition of CN− to the carbonyl carbon.

The cyanide (CN−) ion comes from KCN which dissociates to release K+ and CN−.

KCN is highly toxic, so safety precautions are required.
Formation of Enantiomers
Aldehydes and unsymmetrical ketones can form mixtures of enantiomers when reacting with KCN. See Optical Isomerism for more detail.
Reason: The planar carbonyl group can be attacked from either side, forming two mirror-image products.

There is an equal chance of the carbonyl group being attacked from either side (above or below the plane), meaning a racemic product mixture is made.
Summary
- Aldehydes oxidise to carboxylic acids with acidified K2Cr2O7; ketones do not oxidise under normal conditions.
- Fehling’s gives a brick-red precipitate and Tollens’ gives a silver mirror with aldehydes; ketones show no change.
- NaBH4(aq) reduces aldehydes to primary alcohols and ketones to secondary alcohols via nucleophilic addition of H−.
- Carbonyls react with KCN followed by H+ to form hydroxynitriles; unsymmetrical cases can yield enantiomers.