Electrophilic Addition
Quick Notes
- Alkenes undergo electrophilic addition reactions due to the high electron density of the C=C double bond.
- Common electrophiles:
- HBr – forms halogenoalkanes.
- H2SO4 – forms alkyl hydrogen sulphates (and alcohols (via acid-catalysed hydration)).
- Br2 – forms dihalogenoalkanes (bromine test for unsaturation).
- Unsymmetrical alkenes form major and minor products due to carbocation stability.
- Carbocation stability: Tertiary > Secondary > Primary, influencing the major product that forms.



Full Notes
Addition reactions of alkenes have been outlined in more detail here.
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Mechanism of Electrophilic Addition
Alkenes react with electrophiles in electrophilic addition reactions.
The high electron density within a carbon-carbon double bond attracts electrophiles and the reaction mechanism follows three basic steps:

Step 1: Electrophile Attraction
- The C=C bond has high electron density and attracts electrophiles (electron pair acceptors).
- Electrophiles include H+, Br2, and H2SO4 (see below).
Step 2: Formation of Carbocation Intermediate
- The double bond breaks as one carbon gains a new bond with the electrophile.
- The other carbon becomes positively charged (carbocation).
Step 3: Forming final product
- A negative species (e.g., Br−, HSO4−) bonds to the carbocation, forming the final product.
There are several addition reactions of alkenes you need to know:
2. Addition Reactions of Alkenes
Reaction with Hydrogen Bromide (HBr)
Equation: C2H4 + HBr → C2H5Br
Mechanism:
- HBr is polar (Hδ+—Brδ−), and H+ acts as the electrophile.
- H+ bonds to one carbon of the C=C bond, forming a carbocation.
- Br− attacks the carbocation, forming a halogenoalkane.
Reaction with Bromine (Br2) – Test for Unsaturation
Equation: C2H4 + Br2 → C2H4Br2
Mechanism:
- Br2 is non-polar but gets polarised when approaching the high electron density of the alkene.
- One Br atom bonds to a carbon, forming a carbocation.
- The Br− ion attacks the carbocation, forming a dihalogenoalkane.
Test for Alkenes:
Bromine water (Br2(aq)) turns from orange to colourless if an alkene is present.

Reaction with Sulfuric Acid (H2SO4)
Equation: C2H4 + H2SO4 → C2H5OSO3H
Mechanism:
- H+ from H2SO4 acts as an electrophile, bonding to the alkene.
- Carbocation forms and reacts with HSO4−, forming an alkyl hydrogen sulfate.
- On hydrolysis with water, an alcohol is formed.
- C2H5OSO3H + H2O → C2H5OH + H2SO4
Major and Minor Products in Unsymmetrical Alkenes
When adding an electrophile to an unsymmetrical alkene, two possible products can form.
The two possible products won’t be formed in equal amounts. The product formed most is called the major product and the one formed the least is the minor product.
We can predict the major product based on the carbocation intermediate formed in the reaction – the major product forms from the most stable carbocation.
Alkyl (carbon) groups bonded to the positively charged carbon in the intermediate stabilise the positive charge by ‘giving’ electron density to the positively charged carbon. This is called the positive inductive effect.
The more alkyl groups there are bonded to the positively charged carbon, the more stable the carbocation is and the more likely it is to form.

Carbocation stability order: Tertiary > Secondary > Primary
Example Propene + HBr

Major Product: 2-Bromopropane (Formed from secondary Carbocation)
Minor Product: 1-Bromopropane (Formed from primary Carbocation)
Summary
- Alkenes undergo electrophilic addition because the C=C has high electron density.
- HBr adds to give halogenoalkanes
- Br2 adds to give dihalogenoalkanes and decolourises bromine water
- H2SO4 gives alkyl hydrogen sulphates which hydrolyse to alcohols.
- Mechanism steps: electrophile attack → carbocation formation → anion addition.
- In unsymmetrical alkenes, the major product comes from the more stable carbocation (tertiary > secondary > primary) due to the positive inductive effect.