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*Revision Materials and Past Papers* 1 Atomic Structure 2 Amounts of Substance 3 Bonding 4 Energetics 5 Kinetics 6 Chemical Equilibria & Kc 7 Redox Equations 8 Thermodynamics 9 Rate Equations 10 Kp (Equilibrium Constant) 11 Electrode Potentials & Cells 12 Acids and Bases 13 Periodicity 14 Group 2: Alkaline Earth Metals 15 Group 7: The Halogens 16 Period 3 Elements & Oxides 17 Transition Metals 18 Reactions of Ions in Aqueous Solution 19 Intro to Organic Chemistry 20 Alkanes 21 Halogenoalkanes 22 Alkenes 23 Alcohols 24 Organic Analysis 25 Optical Isomerism 26 Aldehydes & Ketones 27 Carboxylic Acids & Derivatives 28 Aromatic Chemistry 29 Amines 30 Polymers 31 Amino Acids, Proteins & DNA 32 Organic Synthesis 33 NMR Spectroscopy 34 Chromatography RP1–RP12 Required Practicals

1.8 Thermodynamics (A-level only)

1.8.1 Born-Haber Cycles 1.8.2 Gibbs Free Change and Entropy Change

Gibbs Free Energy Change

Specification Reference Physical Chemistry, Thermodynamics 3.1.8.2

Quick Notes

  • Entropy (S) measures the disorder of a system.
    • Change in Entropy (ΔS) measures how the disorder of a system changes for a reaction or process.
  • Gibbs Free Energy Change (ΔG) determines whether a reaction is feasible (spontaneous).
  • Equation for Gibbs Free Energy: ΔG = ΔH − TΔS
      where:
    • ΔG = Gibbs Free Energy change (kJ mol⁻¹)
    • ΔH = Enthalpy change (kJ mol⁻¹)
    • T = Temperature (K)
    • ΔS = Entropy change (J K⁻¹ mol⁻¹)
      (converted to kJ K⁻¹ mol⁻¹ by dividing by 1000)
  • A reaction is feasible (can happen) when ΔG < 0 (negative).
    • Endothermic reactions (+ΔH) can still be feasible if entropy change is positive (+ΔS) and temperature is high.
    • Just because a reaction can happen and is feasible doesn’t mean that it will happen - a high activation energy barrier may prevent a feasible reaction from occurring.

Full Notes

Entropy and Gibbs Free Energy are covered in more detail here.
This page is just what you need to know for AQA A-level Chemistry :)

A reaction that can happen without overall external energy input is called feasible or spontaneous.

Enthalpy change isn’t sufficient to explain why certain reactions are feasible - otherwise, endothermic reactions (+ΔH) would never happen.

To determine whether a reaction is feasible, both enthalpy change (ΔH) and something called entropy need to be considered.

Understanding Entropy (ΔS)

Entropy (S) measures the disorder of a system.

Change in Entropy (ΔS) measures how the disorder of a system changes for a reaction or process.

Greater increase in entropy (more disorder) = More positive ΔS.

Gases have higher entropy than liquids and liquids have a higher entropy than solids as there are more possible ways to arrange the particles (greater potential disorder).

AQA A-level Chemistry Entropy increases from solid to liquid to gas.

Example: We can predict ΔS (change in entropy) by looking at the number of moles of reactants compared to products and their states.


AQA A-level Chemistry Example showing entropy decrease when total moles of gas decrease.

Calculating Entropy Change (ΔS) for a Reaction

Every substance, in a given state, has a standard entropy value (S°).

We can use the standard entropy values (S°) for each substance in a reaction (usually given in tables) to determine the entropy change, ΔS, that occurs for the reacting system (ΔSsystem).

Formula:

AQA A-Level Chemistry calculating entropy change ΔS° = Σ(entropies of products) − Σ(entropies of reactants).
Photo of Matt
Matt’s exam tip

Don’t forget the molar ratios of everything in the equation and keep workings very clear. Also, make sure you are using a substance’s S° value for the correct state (for example, H₂O(l) has a different S° to H₂O(g)).


Worked Example

Calculate ΔSsystem for the following reaction:
2H₂(g) + O₂(g) → 2H₂O(l)

Given:
S°(H₂O(l)) = 70 J mol⁻¹ K⁻¹
S°(H₂(g)) = 131 J mol⁻¹ K⁻¹
S°(O₂(g)) = 205 J mol⁻¹ K⁻¹

  1. Write the expression:
    ΔS = ΣS°(products) – ΣS°(reactants)
  2. Substitute values:
    ΔS = [2 × 70] – [2 × 131 + 1 × 205]
  3. Work out the totals:
    ΔS = 140 – (262 + 205)
  4. Final calculation:
    ΔS = 140 – 467 = −327 J mol⁻¹ K⁻¹

Answer: Entropy decreases in this reaction.

Gibbs Free Energy and Reaction Feasibility

Both the enthalpy change (ΔH) and entropy change (ΔS) of a reaction have an impact on whether the reaction can happen. These can be linked, along with temperature (T), by something called Gibbs Free Energy Change (ΔG).

Gibbs Free Energy Change determines whether a reaction can happen spontaneously (is feasible) under standard conditions.

It can be calculated using:

AQA A-Level Chemistry calculating Gibbs Free Energy Change ΔG = ΔH − TΔS with term meanings.

A reaction is feasible if ΔG is negative (ΔG < 0).

Even if ΔG < 0, a reaction may not occur if activation energy is too high.

Photo of Matt
Matt’s exam tip

Remember to check and convert units when using this equation! Entropy change (ΔS) is always given in J per K per mol, whereas Enthalpy change (ΔH) and Gibbs Free Energy Change (ΔG) are given in kJ per mol. Convert entropy to kJ K⁻¹ mol⁻¹ (divide by 1000).

Conditions for Reaction Feasibility

Condition Effect on Feasibility
ΔH negative, ΔS positive ΔG is always negative
Reaction is always feasible
ΔH positive, ΔS negative ΔG is always positive
Reaction is never feasible
ΔH negative, ΔS negative Reaction is feasible at low temperatures
ΔH positive, ΔS positive Reaction is feasible at high temperatures

Temperature at Which a Reaction Becomes Feasible

To find the minimum temperature (T) at which a reaction is feasible, we can set ΔG = 0:

(If ΔG has to be zero for a reaction to be feasible, then the temperature when ΔG is zero is the minimum that it can be!)

T = ΔH / ΔS
If T is high, the reaction is only feasible at high temperatures.
If T is low, the reaction is feasible at lower temperatures.

Worked Example

Example Calculation: A reaction has the following enthalpy and entropy changes. Find the minimum temperature, T, at which the reaction is feasible.
ΔH = +50 kJ mol⁻¹
ΔS = +100 J K⁻¹ mol⁻¹ (= +0.100 kJ K⁻¹ mol⁻¹)

Use ΔG = ΔH − TΔS and set ΔG = 0:

0 = ΔH − TΔS
T = ΔH / ΔS
T = 50 / 0.100
T = 500 K
The reaction becomes feasible at T ≥ 500 K.

Summary Table: Effect of Temperature on Feasibility

Condition Effect on Feasibility
ΔH < 0, ΔS > 0 Always feasible (ΔG < 0)
ΔH > 0, ΔS < 0 Never feasible (ΔG > 0)
ΔH < 0, ΔS < 0 Feasible at low temperatures
ΔH > 0, ΔS > 0 Feasible at high temperatures

Why Some Feasible Reactions Don’t Happen

Just because a reaction can happen (ΔG is negative) and is feasible doesn’t mean that it will happen - a high activation energy barrier may prevent a feasible reaction from occurring. The rate of reaction may be so slow that the reaction doesn’t happen fast enough to observe.

For example The conversion of diamond into graphite has a negative ΔG, meaning it is thermodynamically feasible. In theory, this process should happen spontaneously.

Diamond to graphite is thermodynamically feasible but kinetically slow.

However, in reality, the transformation does not occur noticeably because it has a very high activation energy (Ea). This large energy barrier prevents the reaction from proceeding at a measurable rate under standard conditions.

Summary