Chlorination of Alkanes
Quick Notes
- Alkanes, such as methane, can react with chlorine in a free-radical substitution reaction.
- The reaction mechanism involves three steps:
- Initiation – chlorine radicals are formed using UV light.
- Propagation – radicals react with methane, forming new radicals.
- Termination – radicals combine to form stable molecules.
- This reaction requires UV light and leads to a mixture of products.

Full Notes
Free-radical substitution has been outlined in more detail here
This page is just what you need to know for AQA A-level Chemistry :)
Methane can react with chlorine in the presence of ultraviolet (UV) light, forming chloromethane.

Further substitution can occur, forming CH2Cl2, CHCl3, and CCl4.
UV light is required to initiate the reaction by homolytic fission.
The reaction is an example of free-radical substitution and occurs in several steps. We can show how the reaction occurs using a mechanism.
Free-Radical Substitution Mechanism

Step 1: Initiation (Radicals Are Formed)
- UV light provides energy to break the Cl–Cl bond by homolytic fission.
- Each chlorine atom ends up with an unpaired electron (•), making it a radical.
Step 2: Propagation (Radicals React and Regenerate)
- Radicals react to form new radicals in a chain reaction.
- Chlorine radical reacts with methane, forming a methyl radical.
- Methyl radical reacts with Cl2, forming chloromethane and a new Cl• radical:
- The process continues, leading to further substitutions (see below).
Step 3: Termination (Radicals Are Removed)
- Radicals combine to form stable (non-radical) molecules, stopping the reaction.
- There are several possible termination reactions:
- Termination stops the chain reaction.

When writing out mechanisms for free radical substitution, make sure you show clearly which species are radicals. And remember - if you start with a single radical on one side of the equation, you must have a single radical on the other side.
Limitations of Free-Radical Substitution
Further substitution can occur, leading to a mixture of products:

This explains why the reaction is difficult to control, leading to multiple side reactions.
Summary Table: Free-Radical Substitution Mechanism
Step | What Happens | Representative Detail |
---|---|---|
Initiation | Cl–Cl bond breaks by homolytic fission under UV to generate radicals. | Cl2 → 2Cl• (UV) |
Propagation | Radicals react with molecules and regenerate radicals (chain process). | Cl• + CH4 → •CH3 + HCl •CH3 + Cl2 → CH3Cl + Cl• |
Termination | Radicals combine to form stable molecules, ending the chain. | Cl• + Cl• → Cl2 •CH3 + Cl• → CH3Cl •CH3 + •CH3 → C2H6 |