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S1.1 - Introduction to the particulate nature of matter S1.2 - The nuclear atom S1.3 - Electron configurations S1.4 - Counting particles by mass - The mole S1.5 - Ideal gases S2.1 - The ionic model S2.2 - The covalent model S2.3 - The metallic model S2.4 - From models to materials S3.1 - The periodic table - Classification of elements S3.2 - Functional groups - Classification of organic compounds R1.1 - Measuring enthalpy changes R1.2 - Energy cycles in reactions R1.3 - Energy from fuels R1.4 - Entropy and spontaneity AHL R2.1 - How much? The amount of chemical change R2.2 - How fast? The rate of chemical change R2.3 - How far? The extent of chemical change R3.1 - Proton transfer reactions R3.2 - Electron transfer reactions R3.3 - Electron sharing reactions R3.4 - Electron-pair sharing reactions

R1.2 - Energy cycles in reactions

1.2.1 Bond Enthalpy 1.2.2 Hess Law 1.2.3 Standard Enthalpies of Combustion and Formation (AHL) 1.2.4 Using Standard Enthalpies (AHL) 1.2.5 Born–Haber Cycles (AHL)

Using ΔHf and ΔHc to Calculate Enthalpy Changes HL Only

Specification Reference R1.2.4

Quick Notes

  • Hess’s Law allows enthalpy changes to be calculated using standard data:
    • ΔH = ΣΔHf(products) − ΣΔHf(reactants)
    • ΔH = ΣΔHc(reactants) − ΣΔHc(products)
  • Enthalpy values are found in the data booklet, units are kJ mol⁻¹.
  • Remember:
    • ΔHf values describe making 1 mole of compound from its elements.
    • ΔHc values describe complete combustion in oxygen.

Full Notes

Instead of drawing out full energy cycles, we can use two standard equations to determine enthalpy change using enthalpies of formation or enthalpies of combustion.

Enthalpy from Formation Data (ΔHf)

Use this equation:
ΔH = ΣΔHf(products) − ΣΔHf(reactants)

Steps:

Worked Example

Calculate ΔH for the reaction C2H4(g) + H2(g) → C2H6(g).

  • Given: ΔHf[C₂H₄(g)] = +52.3, ΔHf[H₂(g)] = 0, ΔHf[C₂H₆(g)] = −84.7
  • ΔH = (−84.7) − (52.3 + 0)
  • ΔH = −137.0 kJ mol⁻¹

Enthalpy from Combustion Data (ΔHc)

Use this equation:
ΔH = ΣΔHc(reactants) − ΣΔHc(products)

This method uses combustion values to “bypass” the target reaction, forming a Hess cycle.

Worked Example

Calculate ΔH for the reaction C₂H₆(g) + Cl₂(g) → C₂H₅Cl(g) + HCl(g).

  • Given: ΔHc[C₂H₆(g)] = −1560, ΔHc[C₂H₅Cl(g)] = −1735, ΔHc[HCl(g)] = −92.3, ΔHc[Cl₂(g)] = 0
  • ΔH = [−1560 + 0] − [−1735 + (−92.3)]
  • ΔH = −1560 − (−1827.3) = +267.3 kJ mol⁻¹

Summary of When to Use Each Equation

Enthalpy Data Used Equation to Use Typical Use Case
Formation (ΔHf) ΔH = ΣΔHf(products) − ΣΔHf(reactants) Most direct, used in standard tables
Combustion (ΔHc) ΔH = ΣΔHc(reactants) − ΣΔHc(products) Often used when formation data isn’t available
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Matt’s exam tip

Important Reminders

  • Use balanced equations and correct molar ratios.
  • Ensure all substances are in their standard states.
  • Values must match the physical states of substances in the reaction.
  • ΔHf of elements in standard states = 0.
  • ΔHc of elements = often 0 for O₂(g), H₂(g), etc.

Summary