AP | A-Level | IB | NCERT 11 + 12 – FREE NOTES, RESOURCES AND VIDEOS!
S1.1 - Introduction to the particulate nature of matter S1.2 - The nuclear atom S1.3 - Electron configurations S1.4 - Counting particles by mass - The mole S1.5 - Ideal gases S2.1 - The ionic model S2.2 - The covalent model S2.3 - The metallic model S2.4 - From models to materials S3.1 - The periodic table - Classification of elements S3.2 - Functional groups - Classification of organic compounds R1.1 - Measuring enthalpy changes R1.2 - Energy cycles in reactions R1.3 - Energy from fuels R1.4 - Entropy and spontaneity AHL R2.1 - How much? The amount of chemical change R2.2 - How fast? The rate of chemical change R2.3 - How far? The extent of chemical change R3.1 - Proton transfer reactions R3.2 - Electron transfer reactions R3.3 - Electron sharing reactions R3.4 - Electron-pair sharing reactions

R3.3 - Electron sharing reactions

3.3.1 Radicals 3.3.2 Homolytic Fission 3.3.3 Practical Substitution Reaction

Homolytic Fission, UV Activation, and Radical Chain Reactions

Specification Reference R3.3.2

Quick Notes

  • Homolytic fission is the breaking of a covalent bond so that each atom gets one electron, forming two radicals.
  • Requires UV light or heat to initiate – e.g., Cl2 → 2Cl•
  • This is the initiation step in radical chain reactions (e.g. halogenation of alkanes).
  • Use a single-barbed arrow (fish hook) to show movement of one electron.
  • CFCs break down in the stratosphere under UV light to release chlorine radicals, not fluorine, due to bond strength differences.
  • Chlorine radicals break down ozone (O3) but not O2 → implies the O–O bond in O3 is weaker than in O2.
  • The reverse of homolytic fission is radical recombination, forming a covalent bond.

Full Notes

Homolytic Fission

Homolytic fission is a type of bond breaking where each bonded atom takes one of the shared electrons, forming two radicals.

It occurs under UV radiation or heat, with a specific amount of energy required to homolytically break the bond.

IB Chemistry diagram showing homolytic fission where a covalent bond splits evenly to form two radicals with one electron each.

Homolytic fission is often the initiation step in a chain reaction, as it produces radicals that can react with stable molecules to form new radicals that can then go on and keep reacting – propagating the process. A key example is free radical substitution in alkanes (see below).

Drawing Homolytic Fission

We can show homolytic fission in mechanisms by drawing single-barbed arrows (sometimes called fish hooks).

IB Chemistry mechanism notation showing single-barbed fish-hook arrows for homolytic fission of a covalent bond.

The arrows start from the bond and point to each species that each get one electron from the bond.

Example Chlorine

Cl2 → 2Cl•

Summary

Linked Course Questions

Reactivity 1.2 — Linked Course Question

Why do chlorofluorocarbons (CFCs) in the atmosphere break down to release chlorine radicals but typically not fluorine radicals?

CFCs (chlorofluorocarbons) contain carbon–chlorine (C–Cl) and carbon–fluorine (C–F) bonds. In the upper atmosphere, ultraviolet (UV) radiation provides enough energy to break the weaker C–Cl bonds but not the stronger C–F bonds.

Bond enthalpy (approximate values):

  • C–Cl: ~340 kJ mol⁻¹
  • C–F: ~485 kJ mol⁻¹

This means:

  • C–Cl bonds undergo homolytic fission under UV light → release Cl• radicals.
  • C–F bonds remain intact because typical UV wavelengths in the stratosphere do not carry enough energy to break them.

Structure 2.2 — Linked Course Question

What is the reverse process of homolytic fission?

The reverse of homolytic fission is called radical recombination.

  • Two radicals combine
  • Each donates one unpaired electron to form a covalent bond

Example Cl• + Cl• → Cl2 (two chlorine radicals recombine to form a chlorine molecule)


Structure 2.2 — Linked Course Question

Chlorine radicals released from CFCs are able to break down ozone (O3), but not oxygen (O2), in the stratosphere. What does this suggest about the relative strengths of bonds in the two allotropes?

This suggests that the bonds in ozone (O3) are weaker than the bonds in oxygen (O2).

Chlorine radicals (Cl•) are highly reactive but still require a certain amount of energy to break a bond.

The fact that Cl• can break the O–O bonds in ozone but not the O=O double bond in O2 means O3 has weaker bonds (lower bond enthalpy) than O2.