Resonance Structures and Delocalization HL Only
Quick Notes:
- Resonance occurs when a molecule or ion has more than one valid Lewis structure with different positions for double bonds.
- The actual structure is a resonance hybrid – a blend of all possible resonance forms.
- Electrons are delocalized across more than two atoms in the molecule.
- We show resonance structures with double-headed arrows (↔) between forms.
- Resonance structures have the same arrangement of atoms, only electron positions differ.
- Common examples include O3, NO3−, benzene (C6H6).
- Delocalization reduces bond length differences and stabilizes the molecule.
Full Notes:
What Are Resonance Structures?
Resonance structures are different valid Lewis structures for the same molecule or ion, where:
- Atoms stay in the same positions
- Electron pairs (especially double bonds) are in different positions
These structures represent the same molecule, not different forms. The actual molecule is a resonance hybrid, meaning the bonding is a mixture of the possible forms.
Delocalization of Electrons
In resonance structures, π (pi) electrons are delocalized (spread over multiple atoms). This creates partial bonding across the delocalized region, resulting in equal bond lengths and increased stability.
Delocalization helps explain unusual bond lengths, stability of polyatomic ions, and the special nature of aromatic compounds like benzene.
Common examples include ozone, carboante ions and benzene.
Example Ozone (O3)

Two valid structures: one double bond between the left O and middle O, or between the middle O and right O. Actual structure: a resonance hybrid where both O–O bonds are intermediate in length and strength.
Example Carbonate ion (CO32−)

Three resonance structures, each with one C=O and two C–O− bonds. In the hybrid all C–O bonds are equivalent in length and strength.
Example Benzene (C6H6)

Six carbon atoms form a ring with alternating single and double bonds. The resonance hybrid has delocalized electrons forming a stable aromatic ring.
Drawing and Recognising Resonance
When drawing resonance structures:
- Use square brackets around resonance structures for ions
- Connect the structures with double-headed arrows (↔)
- Only electron positions change – atom positions stay fixed
Why Are Oxygen and Ozone Dissociated by Different Wavelengths of Light?
Oxygen (O2) and ozone (O3) absorb different wavelengths of light due to differences in their bonding and electron delocalisation.

The oxygen-oxygen bond in O2 is a true double bond, making it shorter and stronger than the bonds in ozone.
In ozone (O3), bonding is delocalised because of resonance. Instead of one single and one double bond, ozone forms a resonance hybrid where both oxygen-oxygen bonds are identical, with bond order between a single and a double bond.
As a result, ozone has no pure O=O double bond, but two longer, weaker bonds than in O2. This makes ozone easier to break, so it absorbs lower-energy (longer wavelength) UV light than oxygen.
In short, the greater delocalisation in ozone reduces the bond strength, explaining why it absorbs different light compared to O2.
Summary
- Resonance structures show different valid Lewis forms of the same molecule with different electron placements.
- The actual structure is a resonance hybrid with delocalized electrons.
- Delocalization explains equal bond lengths and greater molecular stability.
- Examples include O3, NO3−, and benzene.
- Ozone absorbs longer wavelength UV light than O2 because its bonds are weaker due to delocalization.