The Arrhenius Equation HL Only
Quick Notes:
- The Arrhenius equation shows how the rate constant (k) depends on temperature (T) and activation energy (Ea).
- As temperature increases, more particles have energy ≥ Ea meaining k increases (and rate increases).
- Arrhenius equation:
- Linear form (used for graphing):
- A graph of ln k vs 1/T gives a straight line:
- Slope = –Ea / R
- Intercept = ln A
Full Notes:
The Arrhenius Equation, how to rearrange it and using Arrhenius plots has been covered in much more detail at this page and this video. What is on this page and here is just the essentials you need to know for IB Chemistry.
Note: You don’t need to remember the Arrhenius equation - it will be provided in the data booklet in your exams.
The Arrhenius equation shows how activation energy (Ea), temperature (T) and the proportion of collisions with correct orientation (A) can be linked together by the rate constant, k.

Where:
- A = Arrhenius constant (collision frequency factor).
- Ea = Activation energy (J mol⁻¹).
- R = Gas constant (8.31 J mol⁻¹ K⁻¹).
- T = Temperature (K).
This also shows why k increases with temperature as the e-Ea/RT part of the expression gets bigger as T increases.
Linear Form of the Arrhenius Equation
The Arrhenius equation is exponential because it contains ‘e’. To make it easier to work with, we rearrange it to a straight line form by taking natural logs:

This can be rearranged to follow the y = mx + c function of a straight line, where:
- y = ln k
- x = 1/T
- m = –Ea/R (slope)
- c = ln A (intercept)

Arrhenius Plots
Plotting ln k vs. 1/T gives a straight line, following the y=mx+c form of the Arrhenius Equation.
Because of this, the gradient can be used to calculate activation energy:

- Gradient of line = –Ea/R
- Rearrange to find Ea: Ea = –m × R
Summary
- The Arrhenius equation links k, Ea, and T.
- k increases with temperature as more particles exceed Ea.
- Linear form: ln k = –Ea/R × (1/T) + ln A.
- Arrhenius plots (ln k vs 1/T) give Ea from slope.